calc help plzzz

[electronicsgeek 10+ year member]

heres the problem:

how do you find the integral of lx-1l-1 from -1 to 2?

i graphed it and i could use the riemen sums to find the area but im confused on how to go about.

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[Vicodin113 10+ year member]

My head hurts now //content.invisioncic.com/y282845/emoticons/uhoh.gif.c07307dd22ee7e63e22fc8e9c614d1fd.gif

 

[zthumper 10+ year member]

I just got doing like 2 pages of calc probs and im tired of it and i don't feel like thinkin anymore.

 

[j3bus2k3 5,000+ posts]

Man I forget...

It has to do something with Height times width...the width would be 2 since your going from 0 to 8 with 4 intervals; 8/4=2. Then something like 2*f(2)+2*f(4)+2f(6) + 2*f(8)=*the integral from 0 to 8*f(x)dx...I'm totally not sure though and I'm in CalcII

 

[electronicsgeek 10+ year member]

cancel that. grahp is given, stupid me didnt look hard enough.

 

[electronicsgeek 10+ year member]

*bump* new question

 

[thejoker989 10+ year member]

heres the problem:
how do you find the integral of lx-1l-1 from -1 to 2?

i graphed it and i could use the riemen sums to find the area but im confused on how to go about.

If i remember correctly absolute value graphs are not continious so it would be the negative interval of (x-1)-1 from -1 to 1 plus the interval of (x-1)-1 from 1 to 2. Try that and let me know.

Edit:

Actually im pretty sure thats how you do it....