Aero port help

[SicAudio 5,000+ posts]

well thats what we have now...do u know of 2 tens that would sound good ported in a box around that size or a little bigger??

if you are doing external ports try what you have first and see if its what you want dont waste money if you dont need it.

 

[Slo_Ride 5,000+ posts]

would yall please stop.

 

[Slo_Ride 5,000+ posts]

if you are doing external ports try what you have first and see if its what you want dont waste money if you dont need it.

x2

 

[treylittlefield 10+ year member]

wow first sicaudio says oh just throw two 4's in there not realizing that drops it to about 1 cube for each 12 ported. haha then just says oh there shit subs anyway. gtfo you ****

yeah...i dont get it..lol o well

 

[SicAudio 5,000+ posts]

one 6" would need to be 18.87" long. Are you using true flared aeros or pvc?

two 4" would need to be 17.86" long

yes better and just use 2 4" ports made from standard pvc it is just fine.round ports do not need the 12-16" rule and 2 4" ports is 25-26 sq " so its all good.

one 6" = 28.26 sqare inches of port areathree 4" = 37.68 square inches (and they would each need to be 27.76" long)

All lengths are for flared ports, if using non flared then subtract one inch.

ummm....will the port be external?
If not, you do know that the volume will change right? (which means the port length will have to change also to get the desired tuning)

BINGO

and 3 4" ports is way overkill

people keep forgetting that you only need 6-10" per cube with a round port......................

can you read any of this Amartin? where did i say anything even close to what you say i said noob?

 

[treylittlefield 10+ year member]

ok i think i got it thanks //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 

[Slo_Ride 5,000+ posts]

Here it is - you have the subs and the box, put two 4" EXTERNAL aeros on it, or one 6", and see if you like it. If not, try a larger box if you can. Just curious what amp?

 

[SicAudio 5,000+ posts]

That sounds like your telling him to port his 12's with 1 cube each.

after he said it was gonna be external //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

read 1st try to dis when u have a clue //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

 

[treylittlefield 10+ year member]

Here it is - you have the subs and the box, put two 4" EXTERNAL aeros on it, or one 6", and see if you like it. If not, try a larger box if you can. Just curious what amp?

a RF 800watt //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 

[Slo_Ride 5,000+ posts]

I'm fairly sure you will like the ported box better even if it is only 2.5 cubes. If you build your own boxes, or would like to attemp your first, then try about 4 cubes.

 

[treylittlefield 10+ year member]

I'm fairly sure you will like the ported box better even if it is only 2.5 cubes. If you build your own boxes, or would like to attemp your first, then try about 4 cubes.

well its in a single cab truck and the most we could squeeze out is 3cubes...we're gonna port it then if it doesnt sound good we're gonna get subs that will work in that box //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 

[mybrohshi5 10+ year member]

Just a little curious with the aero port calculation displacement.

if 4" aeros at 18" long were used to calculate the cubic feet displacement of this wouldnt you do this?

V=pi(r^2)h ...... so V=3.14(2^2)(18) = 226.08 cubic inches

then cubic inches to feet is 226.08/1728 = 0.13083333 cubic feet

So my question is how are 2 4" aeros causing a displacement of 1 cubic foot?

im confused and want to use aeros on my next box i build haha //content.invisioncic.com/y282845/emoticons/tongue.gif.6130eb82179565f6db8d26d6001dcd24.gif

 

[Slo_Ride 5,000+ posts]

Just a little curious with the aero port calculation displacement.
if 4" aeros at 18" long were used to calculate the cubic feet displacement of this wouldnt you do this?

V=pi(r^2)h ...... so V=3.14(2^2)(18) = 226.08 cubic inches

then cubic inches to feet is 226.08/1728 = 0.13083333 cubic feet

So my question is how are 2 4" aeros causing a displacement of 1 cubic foot?

im confused and want to use aeros on my next box i build haha //content.invisioncic.com/y282845/emoticons/tongue.gif.6130eb82179565f6db8d26d6001dcd24.gif

You would be correct, a 4" cylinder, 18" long = .13. But remember when calculating how much volume a port will take up in a box you have to use the outside diameter of the port, ie. 4.25" for a 4" port. I have no idea where he came up with 1 cube.

 

[mybrohshi5 10+ year member]

You would be correct, a 4" cylinder, 18" long = .13. But remember when calculating how much volume a port will take up in a box you have to use the outside diameter of the port, ie. 4.25" for a 4" port. I have no idea where he came up with 1 cube.

Thanks //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif

 

[302yota 10+ year member]

^^^yeah i was confused about that also...lol