ShiningBuick
10+ year member
NotLoudEnuff
The equation P=V^2 / R, duh.This isnt a way to check and see how much power a amp puts out if thats the case i was getting 104 out of each of my Kicker 1500.1s with nothing on them when i was gain matching them.... How many watts would that be and how are you getting the information to say that you need 66vac at 2 ohms when nothing is hooked to the amp to give it a ohm load??//content.invisioncic.com/y282845/emoticons/rolleyes.gif.c1fef805e9d1464d377451cd5bc18bfb.gif//content.invisioncic.com/y282845/emoticons/rolleyes.gif.c1fef805e9d1464d377451cd5bc18bfb.gif
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The max voltage the amp puts out is going to always be the same, no matter what the load is. But the power that voltage produces changes in accordance with what the subs are wired at.
In his case 2200 watts = 66V^2 / 2 ohms.
It's math, it works //content.invisioncic.com/y282845/emoticons/veryhappy.gif.fec4fed33b4a1279cf10bdd45a039dae.gif

