I'm guessing you have not had formal education in the electricity and magnetism side of physics so I'm just going to tell you straight up.
Current=(volts/resistance) and power=(volts)^2/resistance. These formulas should be used for dirrect current only, but equivalent relations for alternating current are far more complicated (involving trig identities) and these formulas are "close enough"
Now, these forumlas will tell you that voltage and amperage will differ depending on the load (ohmn rating) but the quantity VA (volt*amps) will always be the same.
For those of you in the know, I do realize that the voltage and amperage waves could and probably are out of phase by some degree, but I really don't want to get into an long winded explination to prove myself in this thread
Now, since the power is the same, you MUST look at the efficiency of the woofer to see how loud it will be for a given input of power. Woofers that are rated properly will have an efficiency rating with db/watt as the units. Testing voltages are as follows:
8ohms: 2.828 volts
4ohms: 2. volts
2ohms: 1.414 volts
A woofer with the aformentioned ohm rating must be fed the proper voltage for the sensitivity rating to be correct. If this process was done correctly then the ohmn rating really has no bearing on how loud the woofer will play therefore, you need only worry about ohm rating when you pick the amp you want.
I stand by my assertion that 100 watts into 8 ohmns is exactly the same as 100 watts into 4 ohms no matter the woofer. The voice coils will all carry the exact same amount (approx, we are dealing with AC electricity here) of power, the loudness of the woofer depends on (among a lot of other things) the efficiency of the system.