what wiring variations for dual 4 ohm???

[memphis_vette 10+ year member]

what could i wire 2 dual 4 ohm and 3 dual 4 ohms. the wiring calculators are telling me one thing and people on here are telling me another i just need to know which one is right lol.

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[k_schutte 10+ year member]

2x 4ohm - 1ohm and 4ohm

3x 4ohm - 2.66ohm and 6ohm

people are stupid, use this: http://www.the12volt.com/caraudio/woofer_configurations.asp?Q=3&I=42#results

 

[memphis_vette 10+ year member]

ok thats is what i use lol some guy told me i could run 3 at .66 ohm lol

 

[kr15 5,000+ posts]

i stand corrected, i always thought 3 dvc 4ohm was at .66 when wired paralell...4/6=.66

 

[RAM_Designs 5,000+ posts]

^^^ It is.

Three dual 4ohm subs

.66 = parallel wire each sub down to 2ohms, and parallel them all together

2.66 = series wire each sub to 8ohms, and parallel them all together

6 = parallel wire each to 2ohms, and series them all together.

24 = series wire each to 8ohms, then series them all together

 

[RAM_Designs 5,000+ posts]

ok thats is what i use lol some guy told me i could run 3 at .66 ohm lol

You can, parallel everything.

 

[memphis_vette 10+ year member]

ok hey guys how do you wire 3 subs parallel so i can get .66 ohm?

 

[Cabin_Pressure 10+ year member]

ok hey guys how do you wire 3 subs parallel so i can get .66 ohm?

Land all positives together at positve on amp and land all negatives together on negative at the amp.

 

[kr15 5,000+ posts]

Land all positives together at amp and land all negatives together on negative at the amp

precisely

 

[bubbagumper6 5,000+ posts]

Ok forget the calculator, you just need to understand how to calculate resistance. When you wire two coils in series, you add the values. When you wire them in parallel you follow this formula:

1/Rf = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn

Where Rf is your final impedance load, and R1 - Rn are your individual loads (either coils or subwoofers, etc).

So if you have three dual 4 subs, and wire every coil in parallel you get:

1/Rf = 1/4 + 1/4 + 1/4 + 1/4 + 1/4 + 1/4

1/Rf = 1.5

Rf = 0.667

 

[memphis_vette 10+ year member]

Ok forget the calculator, you just need to understand how to calculate resistance. When you wire two coils in series, you add the values. When you wire them in parallel you follow this formula:
1/Rf = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn

Where Rf is your final impedance load, and R1 - Rn are your individual loads (either coils or subwoofers, etc).

So if you have three dual 4 subs, and wire every coil in parallel you get:

1/Rf = 1/4 + 1/4 + 1/4 + 1/4 + 1/4 + 1/4

1/Rf = 1.5

Rf = 0.667

THANK YOU that makes sense. now i know

 

[Cabin_Pressure 10+ year member]

Ok forget the calculator, you just need to understand how to calculate resistance. When you wire two coils in series, you add the values. When you wire them in parallel you follow this formula:
1/Rf = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn

Where Rf is your final impedance load, and R1 - Rn are your individual loads (either coils or subwoofers, etc).

So if you have three dual 4 subs, and wire every coil in parallel you get:

1/Rf = 1/4 + 1/4 + 1/4 + 1/4 + 1/4 + 1/4

1/Rf = 1.5

Rf = 0.667

And there is the "short-cut" formula for resisitors of the same value wired in parallel: Rt(total ohm value) = R(value of resistor or coil)/N(number of resisitors)

 

[memphis_vette 10+ year member]

wait how does that short cut work? im looking to do 3 dual 4 ohm so add all ohm value...24=4/6????

 

[bubbagumper6 5,000+ posts]

And there is the "short-cut" formula for resisitors of the same value wired in parallel: Rt(total ohm value) = R(value of resistor or coil)/N(number of resisitors)

Yeah I suppose that works, but like you said it's only for when you have the same values (which should be every case in car audio).

 

[bubbagumper6 5,000+ posts]

wait how does that short cut work? im looking to do 3 dual 4 ohm so add all ohm value...24=4/6????

No forget the 24, it's just 4/6 which = .667