SD8000 first impressions

That only works if you have the input power though.. Those amps dont just make power out of thin air. So in a daily seetup surging i'll just figure 600amps, through that one piece of 1/0 input. I would definately see many problems.
Say I was to use an SD8000 and mount it where I would mount my other amp which require about 2.5ft of 1/0 from the battery bank, the SD800 would pull at times 500amps to just make roughly 6kwatts.

You can't tell me they will work well in a "daily" app if you end up melting the wire powering the amp due to surging of current.
Please read all the other topics where I explain why the cable wont melt.

Few Watts are dissipated on the cable and will depends on the average crest factor of the audio signal.

 
Please read all the other topics where I explain why the cable wont melt.
Few Watts are dissipated on the cable and will depends on the average crest factor of the audio signal.
I have given up on trying to convince TNT, being that he is quite an obstinate fellow.

Assume 600A RMS draw for one second, with 1.5' of 2/0 wire.

If I remember correctly it was about 24W of dissipation.

Okay, with that information, I can tell you about how much it will heat for a given amount of time.

First find the volume of the cable, multiply it by the density, then apply the specific heat for the given dissipation upon the mass.

r^2(pi) R is in cm, and so is the length

(((.9266)/2)^2)pi(45.72) = 30.830509 cubic centimeters

30.830509*8.94 g·cm = 275.62475 grams

0.385 J/g•K is the specific heat of copper.

275.62475*.385 = 106.115529

It takes 106.115529J to raise a sample of 275.6g of copper 1 degree kelvin.

24 / 106.115529 = 0.226168594

With 24J per second of heat being dissipated upon 275.6g of copper will raise the sample 0.226168594 Kelvin per second, or 0.407103 degrees Fahrenheit per second. I don't think that's flashing, or melting the insulation instantly. Though, I am not saying the voltage drop is not horrible. xD It will drop about 0.04676V No, I did not type that up on the keyboard, but that's what is what I get from ohms law.

If anyone catches something wrong, please point it out. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

If this is not enough to convince you, I will go on.

Edit: Crap, it was 28W.

28 / 106.115529 = 0.26386336

With 28J per second of heat being dissipated upon 275.6g of copper will raise the sample 0.26386336 Kelvin per second, or 0.474954 degrees Fahrenheit per second. That's a little bit faster, but still is not "OMFG MY WIRE MELTED/VAPORIZED/FLASH/etc"

 
I have given up on trying to convince TNT, being that he is quite an obstinate fellow.
Assume 600A RMS draw for one second, with 1.5' of 2/0 wire.

If I remember correctly it was about 24W of dissipation.

Okay, with that information, I can tell you about how much it will heat for a given amount of time.

First find the volume of the cable, multiply it by the density, then apply the specific heat for the given dissipation upon the mass.

r^2(pi) R is in cm, and so is the length

(((.9266)/2)^2)pi(45.72) = 30.830509 cubic centimeters

30.830509*8.94 g·cm = 275.62475 grams

0.385 J/g•K is the specific heat of copper.

275.62475*.385 = 106.115529

It takes 106.115529J to raise a sample of 275.6g of copper 1 degree kelvin.

24 / 106.115529 = 0.226168594

With 24J per second of heat being dissipated upon 275.6g of copper will raise the sample 0.226168594 Kelvin per second, or 0.407103 degrees Fahrenheit per second. I don't think that's flashing, or melting the insulation instantly. Though, I am not saying the voltage drop is not horrible. xD It will drop about 0.04676V No, I did not type that up on the keyboard, but that's what is what I get from ohms law.

If anyone catches something wrong, please point it out. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

If this is not enough to convince you, I will go on.

Edit: Crap, it was 28W.

28 / 106.115529 = 0.26386336

With 28J per second of heat being dissipated upon 275.6g of copper will raise the sample 0.26386336 Kelvin per second, or 0.474954 degrees Fahrenheit per second. That's a little bit faster, but still is not "OMFG MY WIRE MELTED/VAPORIZED/FLASH/etc"
This.

It's simple physics.

nG

 
I have given up on trying to convince TNT, being that he is quite an obstinate fellow.
Assume 600A RMS draw for one second, with 1.5' of 2/0 wire.

If I remember correctly it was about 24W of dissipation.

Okay, with that information, I can tell you about how much it will heat for a given amount of time.

First find the volume of the cable, multiply it by the density, then apply the specific heat for the given dissipation upon the mass.

r^2(pi) R is in cm, and so is the length

(((.9266)/2)^2)pi(45.72) = 30.830509 cubic centimeters

30.830509*8.94 g·cm = 275.62475 grams

0.385 J/g•K is the specific heat of copper.

275.62475*.385 = 106.115529

It takes 106.115529J to raise a sample of 275.6g of copper 1 degree kelvin.

24 / 106.115529 = 0.226168594

With 24J per second of heat being dissipated upon 275.6g of copper will raise the sample 0.226168594 Kelvin per second, or 0.407103 degrees Fahrenheit per second. I don't think that's flashing, or melting the insulation instantly. Though, I am not saying the voltage drop is not horrible. xD It will drop about 0.04676V No, I did not type that up on the keyboard, but that's what is what I get from ohms law.

If anyone catches something wrong, please point it out. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

If this is not enough to convince you, I will go on.

Edit: Crap, it was 28W.

28 / 106.115529 = 0.26386336

With 28J per second of heat being dissipated upon 275.6g of copper will raise the sample 0.26386336 Kelvin per second, or 0.474954 degrees Fahrenheit per second. That's a little bit faster, but still is not "OMFG MY WIRE MELTED/VAPORIZED/FLASH/etc"
trying to convince me?

so according to your other source of where you are typing up this info, I hope isn't on the 12volt website, it's telling you the single lead of wire can handle a 600amp surge?//content.invisioncic.com/y282845/emoticons/crap.gif.7f4dd41e3e9b23fbd170a1ee6f65cecc.gif

 
Are you fucking dense?
You do realize that music is dynamic? It is not a constant sine wave, by no means. Hook up a high sampling clamp meter to the input of ANY amplifier and look at how often the amperage changes, the peak amperage is by no means the actual amperage over the duration of the amplifier operating.

 

The peak amperage will be for fractions of a second to a few seconds at a time if that... and change dynamically as the music changes.

 

//content.invisioncic.com/y282845/emoticons/fyi.gif.9f1f679348da7204ce960cfc74bca8e0.gif :fyi: //content.invisioncic.com/y282845/emoticons/fyi.gif.9f1f679348da7204ce960cfc74bca8e0.gif :fyi: //content.invisioncic.com/y282845/emoticons/fyi.gif.9f1f679348da7204ce960cfc74bca8e0.gif

 

nG
in your words... "meh"

You think I'm stupid?

I tell you what... Buy one of those amps, hook it up as if it was a daily setup where in most cases requires longer than a foot of 1/0 wire. And burp a 50hz wave full tilt in 3 intervals of 4 seconds. Tell me what happens to the wire. //content.invisioncic.com/y282845/emoticons/thumbsup.gif.3287b36ca96645a13a43aff531f37f02.gif

 
in your words... "meh"
You think I'm stupid?

I tell you what... Buy one of those amps, hook it up as if it was a daily setup where in most cases requires longer than a foot of 1/0 wire. And burp a 50hz wave full tilt in 3 intervals of 4 seconds. Tell me what happens to the wire. //content.invisioncic.com/y282845/emoticons/thumbsup.gif.3287b36ca96645a13a43aff531f37f02.gif
still wouldn't burn up. Even if it did, why would someone do that just to start a fire? People that would use this amp will typically know what they are doing so the ifs ands and maybes you suggest can be dismissed because they aren't gonna happen. The worst result I see from using this amp is someone's voltage dropping so low that either the inline fusing pops or all the electronics of the car shuts off and has to restart.

 
still wouldn't burn up. Even if it did, why would someone do that just to start a fire? People that would use this amp will typically know what they are doing so the ifs ands and maybes you suggest can be dismissed because they aren't gonna happen. The worst result I see from using this amp is someone's voltage dropping so low that either the inline fusing pops or all the electronics of the car shuts off and has to restart.
you wouldn't believe how many idiots are out there buy shit they know nothing about.

So you're saying it will surge the 800amps through a long piece of 1/0?

 
you wouldn't believe how many idiots are out there buy shit they know nothing about.
So you're saying it will surge the 800amps through a long piece of 1/0?
as I said before either inline fuse would blow that the "idiot" has in or the voltage drop would temporarily shut most electronics down in the car, specifically the HU. If the HU shuts off so does the amps because of the remote wire so no burn.

 
as I said before either inline fuse would blow that the "idiot" has in or the voltage drop would temporarily shut most electronics down in the car, specifically the HU. If the HU shuts off so does the amps because of the remote wire so no burn.
I think it would prove virtually useless to even fuse them. I still can't see how 800amps can go through a 2ft piece of 1/0... Maybe I know nothing at all:confused:

 
I think it would prove virtually useless to even fuse them. I still can't see how 800amps can go through a 2ft piece of 1/0... Maybe I know nothing at all:confused:
I played by your parameters, just giving you what would happen if "some idiot" were to run these. It sounds like you think either they won't produce the power or if they do they would cause a fire. Just giving you the reasons why nobody's gonna get hurt even if they don't know what they are doing.

 
People who are worried about wires burning up should stay away from these amplifiers //content.invisioncic.com/y282845/emoticons/fyi.gif.9f1f679348da7204ce960cfc74bca8e0.gif

 
in your words... "meh"
You think I'm stupid?

I tell you what... Buy one of those amps, hook it up as if it was a daily setup where in most cases requires longer than a foot of 1/0 wire. And burp a 50hz wave full tilt in 3 intervals of 4 seconds. Tell me what happens to the wire. //content.invisioncic.com/y282845/emoticons/thumbsup.gif.3287b36ca96645a13a43aff531f37f02.gif
It's physics. The laws of physics. Apparently Makeshift's post went way over your head? Do you not understand ohm's law, simple equations leading to Delta T using the specific heat of copper?

Also, I'll tell you what will happen to the wire. Nothing noticeable. Period.

nG

 
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