hrtbrk1
5,000+ posts
1ManWreckinCrew
yeah i **** at this subject.
A heat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. The same engine running backward is called a heat pump if its purpose is to exhaust warm air into the hot reservoir. Heat pumps are widely used for home heating. You can think of a heat pump as a refrigerator that is cooling the already cold outdoors and, with its exhaust heat QH, warming the indoors. Perhaps this seems a little silly, but consider the following. Electricity can be directly used to heat a home by passing an electric current through a heating coil. This is a direct, 100% conversion of work to heat. That is, 18.0 kW of electric power (generated by doing work at the rate 18.0 kJ/s at the power plant) produces heat energy inside the home at a rate of 18.0 kJ/s. Suppose that the neighbor's home has a heat pump with a coefficient of performance of 3.00, a realistic value.
A.)How much electric power (in kW) does the heat pump use to deliver 18.0 kJ/s of heat energy to the house?
B.)An average price for electricity is about 40MJ per dollar. A furnace or heat pump will run typically 100 hours per month during the winter. What does one month's heating cost in the home with a 18.0 kW electric heater?
C.)What does one month's heating cost in the home of the neighbor who uses an equivalent heat pump?
A heat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. The same engine running backward is called a heat pump if its purpose is to exhaust warm air into the hot reservoir. Heat pumps are widely used for home heating. You can think of a heat pump as a refrigerator that is cooling the already cold outdoors and, with its exhaust heat QH, warming the indoors. Perhaps this seems a little silly, but consider the following. Electricity can be directly used to heat a home by passing an electric current through a heating coil. This is a direct, 100% conversion of work to heat. That is, 18.0 kW of electric power (generated by doing work at the rate 18.0 kJ/s at the power plant) produces heat energy inside the home at a rate of 18.0 kJ/s. Suppose that the neighbor's home has a heat pump with a coefficient of performance of 3.00, a realistic value.
A.)How much electric power (in kW) does the heat pump use to deliver 18.0 kJ/s of heat energy to the house?
B.)An average price for electricity is about 40MJ per dollar. A furnace or heat pump will run typically 100 hours per month during the winter. What does one month's heating cost in the home with a 18.0 kW electric heater?
C.)What does one month's heating cost in the home of the neighbor who uses an equivalent heat pump?
