Jakerrr 10+ year member
Senior VIP Member
for my personal use
(weighing options and considering a loud future system with the limited space I have)
but I figured I might as well share it
doubt anyone will get any use out of this but a few may find it interesting
SA
6 8's fed >4800w : ~2.45 X SPL of 1 SA-15 on 1200w
3 10's >3600w 1.89
2 12's >2400w 1.50
sq root of (product of cone-area and power ratios) = SPL ratio
SPL ratio of 2 (X2 SPL of original system) = 2*(sq rt of 10) dB = ~6.32 dB gain
obvious "in a perfect world" and "all else equal" assumptions made
but measures were taken to decrease likelihood of "overshooting" the ratios
the classic definition of SPL is the one referred to in this model
that is, sound pressure in Pascals/PSI/etc
a ~6.32 dB gain corresponds to pressure (or voltage, albeit with a mythical zero resistance rise) increasing by factor of 2
(weighing options and considering a loud future system with the limited space I have)
but I figured I might as well share it
doubt anyone will get any use out of this but a few may find it interesting
SA
6 8's fed >4800w : ~2.45 X SPL of 1 SA-15 on 1200w
3 10's >3600w 1.89
2 12's >2400w 1.50
sq root of (product of cone-area and power ratios) = SPL ratio
SPL ratio of 2 (X2 SPL of original system) = 2*(sq rt of 10) dB = ~6.32 dB gain
obvious "in a perfect world" and "all else equal" assumptions made
but measures were taken to decrease likelihood of "overshooting" the ratios
the classic definition of SPL is the one referred to in this model
that is, sound pressure in Pascals/PSI/etc
a ~6.32 dB gain corresponds to pressure (or voltage, albeit with a mythical zero resistance rise) increasing by factor of 2