IgnoreMe
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i just wanted to know if you can check this over and tell me if its good?
internal dimensions are 17"H and 28.5"W. the port area i wanted to use was 17x4 so 68 sq inches.
Lv=68*1.84*10^8/[4*1728*(30/.159)^2]-.823*sqrt of 68
Lv=44.061. so that means Physical Lv=44.061-2= 42 inches
now i did 42-21.5(any number smaller than Lv right?)=20.5". length for second wall.
and it displaces 20.5*4.75*17/1728=.9579
the first wall is 20-4=16" lenght for first wall
and it displaces 16*4.75*17/1728=.7476
now for all displacements we get 4+.9579+.7476+.21(for the sub) and that equals 5.9155. so i need an enclosure with a gross volume of 5.9ft^3
now to figure out the depth the box will be i need to do 5.9*1728/(27*17)=22.25
and now 22.25-4(for the port width)=18.25 which is the length for the first port wall
and 42-23.75=18.25 for the second port wall. now is this right or should the 23.75 be a different number? i wouldnt think both port walls would be 18.25" . thanks
internal dimensions are 17"H and 28.5"W. the port area i wanted to use was 17x4 so 68 sq inches.
Lv=68*1.84*10^8/[4*1728*(30/.159)^2]-.823*sqrt of 68
Lv=44.061. so that means Physical Lv=44.061-2= 42 inches
now i did 42-21.5(any number smaller than Lv right?)=20.5". length for second wall.
and it displaces 20.5*4.75*17/1728=.9579
the first wall is 20-4=16" lenght for first wall
and it displaces 16*4.75*17/1728=.7476
now for all displacements we get 4+.9579+.7476+.21(for the sub) and that equals 5.9155. so i need an enclosure with a gross volume of 5.9ft^3
now to figure out the depth the box will be i need to do 5.9*1728/(27*17)=22.25
and now 22.25-4(for the port width)=18.25 which is the length for the first port wall
and 42-23.75=18.25 for the second port wall. now is this right or should the 23.75 be a different number? i wouldnt think both port walls would be 18.25" . thanks
