So i double the wattage once again? I only use that amp at that load for burps.
So you can do this on your own.....you can use simple ohms law to arrive at the "theoretical" power output.
Start with the known figure; 400w RMS at 2ohms.
Using this, we can use ohms law to find the voltage the amplifier is capable of by; V = sqrt(power*impedance).
So, sqrt(400*2) = 28.28V
Now that we know the voltage, we can find the (again, theoretical) power output at any impedance by the formula; power = (voltage^2)/impedance.
So, for 1ohm, (28.28^2)/1 = 799.75w (we'll just round up to an even 800w //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif )
And for .5ohm, (28.28^2)/.5 = 1599.52w (again, we'll round up to 1600w).
So yes, in theory at .5ohm the amplifier should produce 1600w. However, as I said before...this is more of a "perfect world" answer. And as I'm sure you know, the world is rarily perfect //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif. Due to several factors the power output
could be significantly less.
Also depends on if the amplifier is regulated or unregulated. If it's unregulated, the power output will reduce by a decent amount based solely on the drop in your system's voltage.