displacement of aero`s?

thats for port area.

im assuming he means displacement which would be that equation X length of the port divided by 1728.

of course people dont always use the right term to describe what they are talking about so who knows.

port area = pi*R^2 (what dbfan said)

displacement = (pi*R^2) x port length/1728

 
uhh

ignore, in your pursuit to help me, you just confused the hell put of me...

first whats the definition or aeros then? i thought any round port was an aero. im gunna buy the PSP ones. so are those real aeros?

 
uhh
ignore, in your pursuit to help me, you just confused the hell put of me...

first whats the definition or aeros then? i thought any round port was an aero. im gunna buy the PSP ones. so are those real aeros?
by real aeros i meant aero ports. lots of people call regular round pvc ports with no flares, aeros.

they have different ways of calculating their port length.

if your using PSP ports you are in luck, and can use their site as it has a calculator based specifically on their ports with their flare radius' //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

edit: in fact there is no such thing as an "aero port" if its not made by the company. PSP port are round ports with flares, and self made "aero" ports are also just round ports with flares. aero port is a trade marked name used for marketing //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif. sorry to confuse you.

 
heres what i got.

i have a box with a volume of 6 cubes.

two 6 inch ports at 40 HZ means i need 11.49 inch aeros.

H-11.49= .9575

R- 3= .25

so pi*r*r*H= .188 cubes square

two 6 inch ports means .376 cubes of displacment?

 
im a dumbass, i have tried using there site on 3 occasions and i get pissed off and dont finish. it confuses me. thats why im a construction worker...

why does it give me 2 numbers?

by real aeros i meant aero ports. lots of people call regular round pvc ports with no flares, aeros.
they have different ways of calculating their port length.

if your using PSP ports you are in luck, and can use their site as it has a calculator based specifically on their ports with their flare radius' //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif
 
heres what i got.
i have a box with a volume of 6 cubes.

two 6 inch ports at 40 HZ means i need 11.49 inch aeros.

H-11.49= .9575

R- 3= .25

so pi*r*r*H= .188 cubes square

two 6 inch ports means .376 cubes of displacment?
correct. but that is a calculation for a straight port with no flare. the flare is going to add a little bit of displacement (but just a LITTLE bit. you will need to calculate that out if you care enough).

you will probably be at like 5.98^3ft @ 39.8 hz or some shit like that. nothing that will be even REMOTELY noticeable to the ear.

 
im a dumbass, i have tried using there site on 3 occasions and i get pissed off and dont finish. it confuses me. thats why im a construction worker...

why does it give me 2 numbers?
one is a straight length (what you need to cut a straight tube down to) and the other is if you wish to add the PSP flares. at least thats how i understood it.

contact megalomaniac. i know he was dealing with the same issue and didnt understand it, but he was told what it meant in a thread he made. i cant find it right now though //content.invisioncic.com/y282845/emoticons/frown.gif.a3531fa0534503350665a1e957861287.gif

 
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