Crunk Times, My friend.....Crunk Times

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Just lemme know if you need an explanation.
I thought the only way that the second equation could work would be if the negative was on the outside of the cube root because if the negative is on the inside, then you have to have a 1+i(cube root) #....

But I agree with the answer to the first equation.

Correct me if I'm wrong...

 
I thought the only way that the second equation could work would be if the negative was on the outside of the cube root because if the negative is on the inside, then you have to have a 1+i(cube root) #....
But I agree with the answer to the first equation.

Correct me if I'm wrong...
while that is true for square roots, it is possible to take the cube root of a negative number

example: (-1)^3 = -1, (-1)^(1/3) = -1

 
while that is true for square roots, it is possible to take the cube root of a negative numberexample: (-1)^3 = -1, (-1)^(1/3) = -1
CubeRoot.jpg


Now I'm confused //content.invisioncic.com/y282845/emoticons/confused.gif.e820e0216602db4765798ac39d28caa9.gif:confused://content.invisioncic.com/y282845/emoticons/confused.gif.e820e0216602db4765798ac39d28caa9.gif

 
I thought the only way that the second equation could work would be if the negative was on the outside of the cube root because if the negative is on the inside, then you have to have a 1+i(cube root) #....
But I agree with the answer to the first equation.

Correct me if I'm wrong...
Cube roots can have a negative number contained within them without an imaginary answer because it is possible to get an answer from it.

Ie.

sqrt(-9)

What number can you multiply by itself to get -9? 3*3=9 and -3*-3=9, so the answer contains an imaginary number.

cbrt(-27)

What number can you multiply by itself three times gets -27? 3*3*3=27, BUT -3*-3*-3=-27

//content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

 
The first one is 6x^8 IIRC.
cool

sqrt(36x^16) = + or - 6x^8
cbrt(-125[x^24][y^30]) = -5(x^8)(y^10)
Just lemme know if you need an explanation.
yeah, just giving me the answer really doesn't help me

...you can't figure out square root?
no I know how to do square root but I don't recall ever seeing what we are having to do in this class during my highschool years. So sorry that I'm not good at math //content.invisioncic.com/y282845/emoticons/rolleyes.gif.c1fef805e9d1464d377451cd5bc18bfb.gif :rolleyes: I've said a couple of times now that I'm not good in math.

 
so basically what you did with the 125 is figure 5*5*5 = 125 and the other two numbers can both be divided by 3?
Basically, to get the multiplier, you figure out what number can be multiplied by itself the number of times it is being rooted.

Ex. sqrt(100) = 10

And to find the power, you just divide it by the number of times it's being rooted.

Ex. cbrt(x^6) = x^2

That's probably the most basic definition you are going to find.

 
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