3onDubs
10+ year member
Senior VIP Member
PI r squared....isn't the radius 2", so the area is 4 PI...times the length, which is 12", giving us 48 PI. Is that wrong?No.
Your equation for finding the displacment was incorrect. a 4" port 12" long would displace 0.09ft^3.
You do not multiply the Diameter by the length. You first find the surface area using the equation I supplied, then multiply that by the length.
