8 ohms + 4 ohms = ????

he didnt specify if he was using his crossover. so we assume he is wiring it in parrallel with the woofer. of course thats not how its suppose to be done, but let him learn that
//content.invisioncic.com/y282845/emoticons/crazy.gif.c13912c32de98515d3142759a824dae7.gif:crazy://content.invisioncic.com/y282845/emoticons/crazy.gif.c13912c32de98515d3142759a824dae7.gif:crazy://content.invisioncic.com/y282845/emoticons/crazy.gif.c13912c32de98515d3142759a824dae7.gif:crazy://content.invisioncic.com/y282845/emoticons/crazy.gif.c13912c32de98515d3142759a824dae7.gif:crazy:

Yes, let him learn by ruining his shit rather than helping him out in the first place.

 
he just wanted to know what the final load was going to be. if he wanted to ask if he was suppose to wire a 15" woofer with a tweeter then your post would be helpful. just give him the final load and leave it at that.
fail

If a tweeter crossover is used, then the final impedance won't be 2.6 ohmsbecause impedance various with frequency. At high frequency, the amplifier

may see a 4 ohm load, at low frequency, the amp may see an 8 ohm load,

it's a variable.
You shouldn't factor in impedance changes when selecting drivers. Calculating the nominal impedances is the way to go.

 
he didnt specify if he was using his crossover. so we assume he is wiring it in parrallel with the woofer. of course thats not how its suppose to be done, but let him learn that
STFU!

What the fuck is your problem guy? Right now you are in the lead for the Douche Bag of the Year award.

 
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