8 ohms + 4 ohms = ????

OoMesKoO
10+ year member

Me > Newbs. :fyi:
Im putting together a little setup for my HT. Nothing crazy at all. Just 2 15" Electrovoice drivers, with 2 tweeters. But... the tweeter is 4 ohm, and the Electrovoice is a 8 ohm driver. But if i wire them together in parallel, what ohm load does it give?

 
Im putting together a little setup for my HT. Nothing crazy at all. Just 2 15" Electrovoice drivers, with 2 tweeters. But... the tweeter is 4 ohm, and the Electrovoice is a 8 ohm driver. But if i wire them together in parallel, what ohm load does it give?
You don't wire up 15" woofers in parallel with tweeters. You need at least

a tweeter crossover. If you have one, then the amplifier will probably

see the 15" woofer as the hardest load @ 8 ohms, the 4 ohm tweeters

won't stress the amplifier, power consumption is low for tweeters.

 
You don't wire up 15" woofers in parallel with tweeters. You need at leasta tweeter crossover. If you have one, then the amplifier will probably

see the 15" woofer as the hardest load @ 8 ohms, the 4 ohm tweeters

won't stress the amplifier, power consumption is low for tweeters.
Truth...

The tweeter wouldn't last very long wired up with the woofer.

 
You don't wire up 15" woofers in parallel with tweeters. You need at leasta tweeter crossover. If you have one, then the amplifier will probably

see the 15" woofer as the hardest load @ 8 ohms, the 4 ohm tweeters

won't stress the amplifier, power consumption is low for tweeters.
he just wanted to know what the final load was going to be. if he wanted to ask if he was suppose to wire a 15" woofer with a tweeter then your post would be helpful. just give him the final load and leave it at that.

 
2.67 ohms is correct. One simple rule to remember is that when wiring speakers in parallel that the overall load is going to be lower than the lowest impedance speaker. To calculate the impedance, you use this formula or calculator:
http://www.csgnetwork.com/parallelresistcalc.html
just remember the formula for parallel...

1 / [( 1/a ) + ( 1/b )]

a and b are the 2 resistances that are being put in parallel

so for this, it would be:

1 / [( 1/4 ) + ( 1/8 )] = 1 / .375ohms

= 2.67 ohms

 
he just wanted to know what the final load was going to be. if he wanted to ask if he was suppose to wire a 15" woofer with a tweeter then your post would be helpful. just give him the final load and leave it at that.

>>But if i wire them together in parallel, what ohm load does it give?

The post says that both woofer and tweeter are wired in parallel //content.invisioncic.com/y282845/emoticons/laugh.gif.48439b2acf2cfca21620f01e7f77d1e4.gif

This is not how you hook up tweeters.

If a tweeter crossover is used, then the final impedance won't be 2.6 ohms

because impedance various with frequency. At high frequency, the amplifier

may see a 4 ohm load, at low frequency, the amp may see an 8 ohm load,

it's a variable.

How do you think a common loudspeaker with an 8 ohm tweeter,

8 ohm midrange, 8 ohm woofer, three drivers in a cabinet, yield

an 8 ohm impedance ? It's not considered a 2.6 ohm impedance loudspeaker

as each driver has it's own bandpass region.

 
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OoMesKoO

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