5 single 4 ohm subs: final impedance?

[psych0ticnemes1 5,000+ posts]

i know 4 subs gives me a 1 ohm load, but what about 5? //content.invisioncic.com/y282845/emoticons/eyebrow.gif.fe2c18d8720fe8c7eaed347b21ea05a5.gif

Click to read more...

 

[DBfan187 5,000+ posts]

.7-.8ohms

 

[psych0ticnemes1 5,000+ posts]

eek, with impedance rise, think i could run that off a 1ohm stable amp safely?

 

[DBfan187 5,000+ posts]

sure can.

 

[kingpin_jeffie 10+ year member]

depends on the amp

 

[psych0ticnemes1 5,000+ posts]

sure can.

and you are sure it is safe... lol

 

[psych0ticnemes1 5,000+ posts]

...i'm thinking you wanna see me fry my amp and watch it burn //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif

 

[yacob.naif 10+ year member]

What amp? What subs? What enclosures?

If you're running 5 single 4-ohm subs, my gut instinct is that you'd be better off with two dual 4 ohm subs, since you're clearly looking for spl, and most spl subs come in multiple voice coil configurations.

 

[psych0ticnemes1 5,000+ posts]

i know i'm better off running dual 4's, but i want to run 4, just was curious...

and it isn't necessarily and SPL setup, i'm tuning it to 30htz... but i got an awesome deal on all 4 of these subs (Infinity Reference 1240's, 05 model) and i can power them with 300rms to each (their rms) with a concept cc-d1200 which has never ever gotten warm, even when burping an sx 15

enclosure is half built, 8 cubes tuned to 30htz... the 5th was just an idea because they are 30+ shipping

 

[ramos 5,000+ posts]

I would be willing to bet dollars to donuts a 1ohm stable amp will be fine running a .7-.8 ohm load. I ran three 10's at .66 ohm on an older bd1000.1 for two years straight without a problem. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 

[psych0ticnemes1 5,000+ posts]

thank you sir //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 

[Chevyaudio 5,000+ posts]

Yeah you should be fine.

 

[helotaxi 5,000+ posts]

If you need to figure final imp for a number of loads wired in parallel the equation is 1/(1/x + 1/y + 1/z + ...) where the variables are the values of the individual loads in the parallel circuit.

I your case the answer is .8