Wiring Subs to acheive a certain impedance?

4/4/4/4/4/4=.67ohms
4+4+4+4+4+4=24ohms
Clarification on my question:

Can you wire two SVC 4 ohm woofers in series to achieve a single 8 ohm impedance? Once you've wired the three sets of (2) subs then you parallel them to the amp giving a final 2.67 ohm load?

 
I know you can do this with DVC subs and since the subs are basically only resistors and you can wire a circuit in series parallel, then I imagine you could.

 
For some reason im just drawing a blank in my head. Usually I can see the circuit diagram in my head but tonights its just not there

 
Yes4 4 4 4 4 4

series pairs

8 8 8

Parrallel all

2.666666.. ohms

Was this a test? do I win somthing now?

Well that certainly sheds light on something I have been thinking about doing. I was thinking of taking (6) dual 2 ohm subs and series wiring each sub, then series wiring them again in pairs, and finally paralleling them to the amp for a 2.66666.... ohm load?? What do ya think? Can it be done? Is there a good chance I will fry something??

 
jsloan told you make three sets of series wired subs then parallel those three to the amp.

I guess I just didn't realize jsloan was the expert. His answer was clear when it came to the mathematics, but it didn't do a very good job of helping me with my application.

 
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