wiring question

0.6 ohms

R(total) = 1 / ((1/r1) + (1/r2) + (1/r3) ... (1/rn))

R(total) = 1 / ((1/4) + (1/4) + (1/4) + (1/4) + (1/6) + (1/6) + (1/6) + (1/6))

R(total) = 1 / (1 + .66666)

R(total) = 0.6

 
0.6 ohms

R(total) = 1 / ((1/r1) + (1/r2) + (1/r3) ... (1/rn))

R(total) = 1 / ((1/4) + (1/4) + (1/4) + (1/4) + (1/6) + (1/6) + (1/6) + (1/6))

R(total) = 1 / (1 + .66666)

R(total) = 0.6
The picture is a series/parallel, not parallel/parallel.

I got 10 ohms.

 
it's just what i had laying around, but i think that i may go with just using two of them. i have two 12" JL Audio 12W3D4's and two 12" American Bass VFL1266's. right now the amplifiers i have to choose from are a JL Audio 250/1 and a Rockford Punch 800.2, which would you go with?

 
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