Wiring 3 subs....... HELP

Jaredturp
10+ year member

CarAudio.com Elite
So here is the setup:

2 DD 1508's (S4)

1 10" Fi SSD (??)

1 2610d Hifonics Brutus

So I want to give the DD's 1300 to split and the SSD 1300

I wire the DD's in parallel so I have 2 ohms

Then I wire the SSD to 2 ohms as well

put the DD's and the SSD in parallel and that gives me 1 ohm

But do all subs recieve equal power?

Or do the DD's split 1300?

Thanks in advance,

Jared

 
Sounds like the DD's would split the 1300 and the SSD would see 1300 alone. That's gonna offset the subs when flexing. Major phase problems are in the near future for you. Why not just sell the SSD 10", buy and 1508 and call it a day....//content.invisioncic.com/y282845/emoticons/fyi.gif.9f1f679348da7204ce960cfc74bca8e0.gif

 
It's not for me man.. A buddy really wants to do this in his truck... I suggested against it, but he is a stubborn guy, but i was interested in this power wise (which subs get what)

 
It's not for me man.. A buddy really wants to do this in his truck... I suggested against it, but he is a stubborn guy, but i was interested in this power wise (which subs get what)
Tell your friend he's an idiot. Then sell that SSD 10" and buy 1 or 2 1508's. Will sound better and be louder than the previous idea.

 
no. retarded idea. buy a dual 2 ohm sub that will take 2krms or 2 dual 4 ohm subs that will take 1k a piece. ( if im not mistaken that amp does "2600" 2K OR so @ 1ohm)
It's going in a truck man... the 1508's behind the seat and the SSD was to go in a box replacing the console.

 
no it doesnt whichever sub is the most efficient is gonna take most of the amps power way more than 1300
BRWRONG.

Efficiency is the ability of the subwoofer to convert input power to output sound with an amount lost due to heat/friction. Input power is dependent on the wiring.

Say all the woofers are wired to 4 ohms, and then all parallel to the amp. Each woofer is going to get exactly 1/3 of the power output of the amp. The amount of heat lost and sound output will be determined by the sub's efficiency.

 
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