wiring 2 ohm subs??

95Prober
10+ year member

CarAudio.com Elite
well, my brother was looking to grab a bunch of 8" woofer at 2 ohms each on a single voice coil. the thing is, i checked the wirign charts but cant find what FINLA load i can get by wiring together several 2ohm SVC subs?? does anyone have a list going fron 2 subs together and up ?? parallel / series and series/parallel ?

thx

 
Wiring the VC's together on each sub simplifies the process.

You can have X amount of 1ohm woofers or 4ohm woofers to work with this way.

 
How many is "a bunch"...

well not decided yet. but i think he found a good deal on 8" ers. they are ALL 2 ohm SVC subs.

i found a chart already for "PARALLEL" so i dont need help there.

but i'd like a chart for - SERIES and SERIES/PARALLEL , that is if u CAN wire them those ways??

im assuming (4) 8 " subs at the moment, possible 5 or 6

 
Resistance in a series circuit will be additive. Meaning, just add all of the resistance of each sub ( four 2 ohm SVC speakers = 8ohms )

I wouldnt reccomend doing them this way, as it would come out to too much resistance with that many speakers. Parallel is the way to go...

 
Reduce the overall number by pairing the subs in either parrallel or series (1 or 4ohm)

A calculator and a pen and paper is all you need to figure out possible wireing combo's

For series you just add up the coils

For parrallel you divide 1 by the ohms of the coil and then multiply the answer by how many subs you plan to parrellel.

Example

three 4ohm subs

1 divided by 4 (the 1 is the constant)

This equals .25

Multiply by three because there is three 4ohm subs

.25 X 3

this equals .75

now take that total for all the woofers and divide that into 1

1 divided by .75

this equals 1.3333

1.3 is the ohms

 
Reduce the overall number by pairing the subs in either parrallel or series (1 or 4ohm)A calculator and a pen and paper is all you need to figure out possible wireing combo's

For series you just add up the coils

For parrallel you divide 1 by the ohms of the coil and then multiply the answer by how many subs you plan to parrellel.

Example

three 4ohm subs

1 divided by 4 (the 1 is the constant)

This equals .25

Multiply by three because there is three 4ohm subs

.25 X 3

this equals .75

now take that total for all the woofers and divide that into 1

1 divided by .75

this equals 1.3333

1.3 is the ohms

If you have a calculator for any type of modern math, you can use the inverse button which is x^-1 I believe.

 
Reduce the overall number by pairing the subs in either parrallel or series (1 or 4ohm)A calculator and a pen and paper is all you need to figure out possible wireing combo's

For series you just add up the coils

For parrallel you divide 1 by the ohms of the coil and then multiply the answer by how many subs you plan to parrellel.

Example

three 4ohm subs

1 divided by 4 (the 1 is the constant)

This equals .25

Multiply by three because there is three 4ohm subs

.25 X 3

this equals .75

now take that total for all the woofers and divide that into 1

1 divided by .75

this equals 1.3333

1.3 is the ohms
so (6) 2 ohm SVC subs will give me a final load of "3 ohms" in parallel. think its right

 
re 8's are svc2 arent they??
Also stones, your math is a little off. These are single VC 2ohmers. So in parallel a pair would be 4ohms, and three 4ohm resistors wired in parallel would be 1.33ohms
actually if you wired 2 svc2 ohm subs together in parallel you would get 1 ohm then the 3 pairs in parallel would yield 0.33 ohms now if you wired the subs in series then the sets in parallel you would get 1.33

 
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