What's the volume of this box?

[3onDubs 10+ year member]

I want to modify the following box to be 6 inches deeper. In other words, the depth of the bottom of the box will be 2'4" instead of 1'10". The depth of the top of the box will be 1'9" instead of 1'3". All other measurements will remain the same.

Can anyone help me find the volume of each chamber after port and sub displacement? The subs are idmax's and the port is 4" wide, 11" long.

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[hofulstrof 10+ year member]

take the area of the panel on the left and miltilpy it by the width (2' 4.5") and divide by 1728

 

[hofulstrof 10+ year member]

actually if you multily the area left pannel by 2' 3.75" if will also take into accout the displacemnt of the middle pannel:

oh and here'a another tip

click on:

window

model info

units

formant and change it to decimal

then click on precision and change it to 0.00

 

[3onDubs 10+ year member]

Thanks hofulstrof....So far i've got the following:

Rectangle section...4.7 cu. ft.

Triangle section...0.75 cu. ft.

Port volumes (both)...0.16 cu. ft.

Total box volume = 5.45 - 0.16 (port displacement) = 5.29 cu. ft.

I need this box to be 5 cu. ft. or slightly under after i calculate in the sub displacement. Does anyone know approximately what the displacement would be for the two 12" IDMAX's?

 

[hofulstrof 10+ year member]

.1cf? also pm sent

 

[James Bang 5,000+ posts]

Well, I will be building this box. What would be the tuning of that 4"x11" port per 2.5 cube chamber? just wondering, because he wants it to be approx 32hz.

 

[hofulstrof 10+ year member]

yes its tuned to 32

 

[James Bang 5,000+ posts]

yes its tuned to 32

yes //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif