Using Xover as connection point?

All_Logix
10+ year member

Formerly CivicGTi
OK, I know this is a really dumb question but I am going to ask it anyway...suppose I have some Xovers under my seats and I have decided to go with an active bi-amp solution for my front components. Now the crossovers are kinda in there pretty good and I dont have a soldering iron on hand....what would happen if I disconnected the input on the xover (from amp) and put it in the connection for the woofer out so that the woofer out connection would have both the line from the amp and the line out to the woofer, then ran a wire from the amp to the tweeter out connection so it would have a line from the amp and a line to the tweeter at this connection.......would this work or just fry the xover

amp--------------(W-)Xover(W-)------------Woofer(-)

amp--------------(W+)Xover(W+)------------Woofer(+)

amp--------------(T-)Xover(T-)-------------Tweeter(-)

amp--------------(T+)Xover(T+)-------------Tweeter(+)

 
Yeah this is the route I would take normally, I ask because the crossovers are mounted in there so well I would have to take the seats out to get them out and it would drive me crazy to know I have crossovers sitting there with no wires attached to them....I was just wondering if it would work

 
The grounds are tied on the crossover, and therre is a load. Don't do it. Depending on the slope, there may be a cap to negative on the speaker side, which is a short. look at the board, draw a schematic, and do the calc. Should be easy for an EE.

Pull your seats, only 4 bolts and 5 min.

Or insert a standard terminal block in its place.

 
HAHA, thanks man I actually did EXACTLY that, I decided not to take the chance and then after I got them out I wondered if it would work so took the xover to class and the professor and I calculated it out. DO NOT EVER DO WHAT I SUGGESTED ABOVE

 
I posted this in another thread, thinking it was this one. got me all mixed up... //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif i'll put it here for others looking for similar information.

remember that for a series DC circuit: a cap looks like an open circuit and an inductor looks like a short circuit. therefore; for low frequencies (almost DC) the cap is still an open circuit (high pass) and the inductor is still a short circuit (low pass).

two quick links on passive crossovers

Passive Crossover Network Design

Designing Passive Crossovers

these show configurations for various slopes. if you have a 12dB/oct crossover (common) you will have a short circuit if you used the terminal block to land wires.

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All_Logix

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