quick question

[JAZN 5,000+ posts]

dont really see it their either

Maybe you're not understanding cuz we're not on the same page.

Which of these is the problem?

1) x=2y-1/(3y)+3

2) x=2y-(1/3)y+3

3) x=(2y-1)/(3y+3)

 

[JAZN 5,000+ posts]

Is the problem supposed to be x= (2y-1)/(3y+3)? If not, ignore the following...

If so:

1) multiply both sides by (3y+3) --> 3xy+3x=2y-1

2) subtract 2y from both sides --> 3xy-2y+3x=-1

3) subtract 3x from both sides --> 3xy-2y=-3x-1

4) factor out y --> y(3x-2)=-3x-1

5) divide both sides by (3x-2) --> y=(-3x-1)/(3x-2)

 

[flakko 5,000+ posts]

^^^^ stereotype...

 

[Gauntlet 5,000+ posts]

1) multiply both sides by (3y+3) --> 3xy+3x=2y-1

2) subtract 2y from both sides --> 3xy-2y+3x=-1

3) subtract 3x from both sides --> 3xy-2y=-3x-1

4) factor out y --> y(3x-2)=-3x-1

5) divide both sides by (3x-2) --> y=(-3x-1)/(3x-2)

See last post on first page

 

[electronicsgeek 10+ year member]

Haven't taken a math class in four years, I think this is what you do
(3y + 3)x = 2y - 1

3xy + 3x = 2y - 1

2y - 3xy = 3x + 1

y(2 - 3x) = 3x + 1

y = (3x + 1) / (2 - 3x)

that is correct...thank you very much

 

[JAZN 5,000+ posts]

See last post on first page

yea yea you're too quick for me bastage //content.invisioncic.com/y282845/emoticons/tongue.gif.6130eb82179565f6db8d26d6001dcd24.gif

 

[dbhittin 5,000+ posts]

i wouldn't even know where to start

 

[sumone 10+ year member]

x = 2y - 1/3y + 3

x = (5 / 3)y + 3

x + 3 = (5 / 3)y

(x + 3) / (5 / 3) = y

(3(x + 3)) / 5 = y

(3x + 9) / 2 = y

IF you go by how it was written...i.e. OofO

 

[creater 10+ year member]

x = 2y - 1/3y + 3x = (5 / 3)y + 3

x + 3 = (5 / 3)y

(x + 3) / (5 / 3) = y

(3(x + 3)) / 5 = y

(3x + 9) / 2 = y

IF you go by how it was written...i.e. OofO

doesnt +3 become -3 when u take it over to the other side of the = ????

 

[JAZN 5,000+ posts]

That's not even the right problem so who cares

 

[sumone 10+ year member]

doesnt +3 become -3 when u take it over to the other side of the = ????

Nope. Because you can you Politifoobar's principle: ignore all arithmetic errors.

 

[ighettoboyi 10+ year member]

for an indian geek you're pretty dumb

 

[Silver 10+ year member]

im having a brain freeze...

x=2y-1/3y+3

how do i slove for y?

is it 3y or -1/3y?

like terms mafuka