Once you understand what the box does to affect cone excursion, the answer to this thread becomes obvious.
What Im talking about is the 'air spring' the box creates. When a sub, which is mounted in an enclosure (sealed or ported), is moving, the cone motion affects the air molecules inside the box. As the cone moves in, the air molecules are compressed. When the cone moves out, the air molecules are expanded. The smaller the box, the more each air molecule must be compressed in order to achieve a given cone excursion. The bigger the box, the more molecules inside it, so the less each molecule must compress (or expand). So common sense tells us that the larger the box, the less 'air spring' is placed on the cone motion, the easier the cone is, and the more efficient the speaker/enclosure is (because the cone can move easier). This is especially true for lower freqs, because the lower the frequency, the more air that must be displaced in order to reproduce that note. This is why larger boxes exaggerate the lowest octaves.
And yes, even in ported boxes the air is compressed. The size of the port (length and port area) is small enough to restrict air flow, and it is that restriction that means the air molecules must be compressed. What changes, in regards to this discussion, with ported boxes, is that how close the note being played is to the tuning point of the enclosure affects the resistance the port places on air flow, cone excursion, and air compression inside the box.