Port...... SMH!!

bgowdy
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Ok this gets kind of annoys me. Everytime i think i figure something out, i read something that completely throws a wrench into plan lol.

But anyway... To the port. When im trying to figure out amount of port i need(the square inches of port per cube), do i base the amount of port off of the gross internal volume or what?

When you come up with the outer dimensions for the enclosure, Example-L x W x H = gross volume internal. When i look at my dimensions and try and figure out how many "square inches of port per cube" that i want. Do i divide the total square inches of the port(EX- 1-12" aeroport equals 113.04sqin's) by the gross internal volume(EX- 11.07 cubes internal ***berfore displacement***) to figure the amount of square inches of port per cube(EX- 113.04 / 11.07 = 10.21 sqin^3 per cube)? is this the correct way to look at it, or do you divide by the internal net volume(***after displacement***)? (EX- 113.04 / 9.85 = 11.48 sqin^3 per cube)

which way is correct??????

hope this isnt to confusing,

thanks,

 
anything like that is calculated with net internal volume. the woofer sees net volume as acoustical suspension and tuning to based off of such

 
anything like that is calculated with net internal volume. the woofer sees net volume as acoustical suspension and tuning to based off of such
i know its internal vol. so i go off the volume before any displacement right

 
i know its internal vol. so i go off the volume before any displacement right
no... thats gross volume. i said net internal volume. And yea as noted its not really the best way to calculate how much port area you need

 
After all displacements.

hm.... well if thats the case, i will have more square inches of port per cube then i thought, possibly to much, but idk. Im running 2 18" OA 18s on 3k. Is 11.48 inches of port per cube to much for a daily driver with potential to put up decent term-lab numbers?

 
hm.... well if thats the case, i will have more square inches of port per cube then i thought, possibly to much, but idk. Im running 2 18" OA 18s on 3k. Is 11.48 inches of port per cube to much for a daily driver with potential to put up decent term-lab numbers?
i dont know your tuning but you need about 200" of port for those subs and 20mm of xmax.

 
As stated above - necessary port area is not some arbitrary amount in relation to the size of the enclosure.

It's based on parameters of the woofer - and the tuning of the enclosure (the tuning of which 'does' have a relationship with the size).

hm.... well if thats the case, i will have more square inches of port per cube then i thought, possibly to much, but idk. Im running 2 18" OA 18s on 3k. Is 11.48 inches of port per cube to much for a daily driver with potential to put up decent term-lab numbers?
 
i dont know your tuning but you need about 200" of port for those subs and 20mm of xmax.
im using an aeroport, not a slot port. Aeros usually need about 1/2 the amount of port vs a slot. theres no way is should need 200 inches of port

 
im using an aeroport, not a slot port. Aeros usually need about 1/2 the amount of port vs a slot. theres no way is should need 200 inches of port
Well then you would need 4 6" aeros. Honestly a 220 sq. inch slot port would be louder. Aeros dont quite work as well when u start using a bunch of them.

 
Well then you would need 4 6" aeros. Honestly a 220 sq. inch slot port would be louder. Aeros dont quite work as well when u start using a bunch of them.
thats why i would be using less ports, i know less ports are more efficient when using aeroports.

4 - 6" = 113.04

2 - 8" = 100.48(close enough)

1 - 12" = 113.04(i more and likely would be using the 1-12")

also i dont have the room for slot port box

 
0_o

While you can get by with less port area using aerports - it's no where near half... More like 15-20%

im using an aeroport, not a slot port. Aeros usually need about 1/2 the amount of port vs a slot. theres no way is should need 200 inches of port
 
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bgowdy

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