CranberryYumYum
10+ year member
Senior VIP Member
box dimensions
38 * 13 * 15.98=
7894.12 in³ =
4.56835 ft³
tuned to 32hz
Bracing with 1 in dowel rod
up/down
r=.5 h=15.95
3.142 * .25 * 15.94 =
12.5 in³ =
0.007233 ft³
front/back
r=.5 h 12.97
3.142 * .25* 12.97 =
10.188 in³ =
0.005895 ft³
probably two of these.. perpendicular or parallel
so this leaves either 4.553884 for parallel or 4.555222 for perpendicular, up/down and front/back
plus sub displacement of .19
4.363884 parallel..........
and for port area, with 57.25 in² slotted, ~50% for aero is 28.625 in²
so a 6in aero port will be about 13.62 in long with the flare, with 28.26 in² without. round is also about 55% more efficient than slot so.. i think all my math is good, but someone may prove me wrong
so that's a displacement of 366.2 in³ = 0.211921 ft³
with displacements in consideration it is 4.151963 ft³
how would i bring this into my equation? average the non displaced and the displaced and take that and use it in the equation, or should i simply add the displacement of the port BACK into the box dimensions and forget about everything else? //content.invisioncic.com/y282845/emoticons/yumyum.gif.0556df42231b304b9c995aefd13928a8.gif
yes, the winisd is modeled in a slotted enclosure but i did all the calculations separate, with the vent at 0
i'll use mdf this time //content.invisioncic.com/y282845/emoticons/fyi.gif.9f1f679348da7204ce960cfc74bca8e0.gif
thanks in advance guys
38 * 13 * 15.98=
7894.12 in³ =
4.56835 ft³
tuned to 32hz
Bracing with 1 in dowel rod
up/down
r=.5 h=15.95
3.142 * .25 * 15.94 =
12.5 in³ =
0.007233 ft³
front/back
r=.5 h 12.97
3.142 * .25* 12.97 =
10.188 in³ =
0.005895 ft³
probably two of these.. perpendicular or parallel
so this leaves either 4.553884 for parallel or 4.555222 for perpendicular, up/down and front/back
plus sub displacement of .19
4.363884 parallel..........
and for port area, with 57.25 in² slotted, ~50% for aero is 28.625 in²
so a 6in aero port will be about 13.62 in long with the flare, with 28.26 in² without. round is also about 55% more efficient than slot so.. i think all my math is good, but someone may prove me wrong
so that's a displacement of 366.2 in³ = 0.211921 ft³
with displacements in consideration it is 4.151963 ft³
how would i bring this into my equation? average the non displaced and the displaced and take that and use it in the equation, or should i simply add the displacement of the port BACK into the box dimensions and forget about everything else? //content.invisioncic.com/y282845/emoticons/yumyum.gif.0556df42231b304b9c995aefd13928a8.gif
yes, the winisd is modeled in a slotted enclosure but i did all the calculations separate, with the vent at 0
i'll use mdf this time //content.invisioncic.com/y282845/emoticons/fyi.gif.9f1f679348da7204ce960cfc74bca8e0.gif
thanks in advance guys
