Math Time :d

the727kid
10+ year member

CarAudio.com Veteran
Alright, so if to set my gains is SqRoot of watts times ohms. Ex. I want 1000 watts, I would do Sqroot(1000x2)...which would be 44.72, correct?

But to my question at hand, if I did the oppisite, without knowing what watts but what sounds best, would the watts I found from doing the equation, Voltage squared divded by ohms to figure out my watts, EX. (44.72x44.72)/2 , which equals roughly 1000watts, would that be my PEAK watts, or my RMS watts.

I have heard both sides, I am leaning towards it is my PEAK watts because I know on music my voltage never becomes that high. And if it is, is there any way to figure out my RMS watts without a O-scope?

 
http://www.the12volt.com/ohm/ohmslaw.asp
yes, you are correct. it works both ways.

if youre multimeter measures RMS voltage, you will be calculating RMS wattage.

i'm not sure you really understand the terms peak and RMS.
Well obivously I know peak is the peak output power and RMS is the what it constantly put its out. Is it more in depth than that?

And how can I tell if my DMM is measuring RMS?

 
Well obivously I know peak is the peak output power and RMS is the what it constantly put its out. Is it more in depth than that?
And how can I tell if my DMM is measuring RMS?
rms and peak have nothing to do with short bursts vs. constant output.

both would be measured with a constant sine wave. the DMM would measure the RMS voltage, which is 0.707*peak voltage. after you run it through the proper ohm's law equation this results in RMS wattage (power) being half of peak power.

 
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