L-port vs. "zig-zag" port...

[jeepintn 10+ year member]

is there any audible difference in an "L" shaped port or a "maze" type zig zag port? is there any difference in how u measure for them? i.e. center line...

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[lilmaniac2 5,000+ posts]

only diff i ever seen is sometimes its more effiient use of space if u do the zig zag vs a l shape.. alot depends on port area and width of box

 

[iamamp3pimp 5,000+ posts]

zig zag/maze is called a labrynith, and they are harder to design, but not by much. the more turns, the more turbulence...as we all know, air is like water, and it likes to follow the path of least resistance.

 

[jeepintn 10+ year member]

well, the reason i am asking is i have designed my box to have two ports, each 34.5 inches long, with the box only being 30 inches deep and 39 inches wide. after correction, etc, there will be an are of about24 inches between the innermost part if each "L" shaped port... and if i went with a labyrinth, there would be much more room there... jsut didnt know if it would be worth going through the trouble of doing it that way, but i think 24" should be enough

 

[iamamp3pimp 5,000+ posts]

yeah 24 inches is more than enough.

 

[knotslck 10+ year member]

L > zig zag from what i understand.

 

[iamamp3pimp 5,000+ posts]

I agree. Less turns = less turbulence.

not that you really notice any of it though

 

[jeepintn 10+ year member]

ok, yesterday, i was adding wrong, i dont know what i was doing. there will actually be 15" of width between the ends of each "L" port... is that enough?

 

[yacob.naif 10+ year member]

some people seem to think more tuns = less speaker slop (ie; the turbulance causes more pressure inside the box)

i don't know if there's any truth to that or not

 

[iamamp3pimp 5,000+ posts]

whats the witdh of the port again?

 

[jeepintn 10+ year member]

its 4" wide... and the elbow part will be 8.5" long each wide, so a total of 12.5 each side coming in... which would only leave 14" between the ports, being that the box is 39" wide

 

[PowerNaudio 10+ year member]

you will be ok with at least 8" gap between the two ports.

the labyrinth enclosure wich is also know as a TL enclosure uses a difrent tuning equation

The length of the line is calculated Using:

v

λ=------

f

where:

λ = wavelength in metres

v = velocity of sound in long-haired wool = 330 × 0.85 m/s

f = the resonant frequency of the woofer = "35Hz example"

330 x 0.85

λ=---------------- =8m

35

but im sure thats not what you had in mind.

and you calculate your port in this maner.

im not 100% on this but. adding 180* bends to the port will slow the air down. the more folds you add to the port the lower your tuning freq will be from the calculated value. how drastic of a change this is im not sure.

laters

 

[jeepintn 10+ year member]

you will be ok with at least 8" gap between the two ports.
the labyrinth enclosure wich is also know as a TL enclosure uses a difrent tuning equation

The length of the line is calculated Using:

v

λ=------

f

where:

λ = wavelength in metres

v = velocity of sound in long-haired wool = 330 × 0.85 m/s

f = the resonant frequency of the woofer = "35Hz example"

330 x 0.85

λ=---------------- =8m

35

but im sure thats not what you had in mind.

and you calculate your port in this maner.

im not 100% on this but. adding 180* bends to the port will slow the air down. the more folds you add to the port the lower your tuning freq will be from the calculated value. how drastic of a change this is im not sure.

laters

dang. thanks for that info man. thanks A LOT.

 

[iamamp3pimp 5,000+ posts]

thats cool.

 

[PowerNaudio 10+ year member]

dang. thanks for that info man. thanks A LOT.

anythime! if i have the time! lol

laters