Gonna make a new enclosure

and you have no bracing in that big *** thing?



maybe if you brace it it may help.
that is wut I think it is, but since ill be making a new box(better made, brace and all ), 4.3net @31hz with 67.5 sq.inch of straight port should be enough for no noise? or i could do 4cu.ft NET @35hz with 81sq.inch...

 
why 50 HZ?
he wants more lows.

lol
LoLz

i had an old box (first one) 2.9NET @ 49hz , spl monster, still sounded nice when u eq a bit, cuz of the woofer I guess, NO air noise I was aware of even with the lows, it just bottom out so easily and lose lot of output below around 37hz-40hz...

that was with 15.5 x4 (62sq inch of straight port, moved LOT OF AIR)

 
I don't like L-Ports, they waste space imo .

I have a labyrinth right now, its the biggest box I can put, I could add 1inch more in width

That is why, straight port seems like the easiest and save the most space and would have the least turbulence. Im debating on how much sq inch should I make and why do I have port noise on low notes...also, does too big of a port make port noise?

 
I don't like L-Ports, they waste space imo .
I have a labyrinth right now, its the biggest box I can put, I could add 1inch more in width

That is why, straight port seems like the easiest and save the most space and would have the least turbulence. Im debating on how much sq inch should I make and why do I have port noise on low notes...also, does too big of a port make port noise?
how do you figure?

just look at these two boxes:

labyrinth:

http://www.subwoofertools.com/forum/ported-box.asp?Ew=38&Eh=14&Dia=6&Xmax=23&Vd=.1&NumW=2&Vb=4&Fb=30&Qts=&Vas=&Fs=&CE=0

l-shaped:

http://www.subwoofertools.com/forum/ported-box.asp?Ew=48&Eh=14&Dia=6&Xmax=23&Vd=.1&NumW=2&Vb=4&Fb=30&Qts=&Vas=&Fs=&CE=0

they both have the same net volume, tuning frequency, port area and port length.

since both ports have the same lenght and area they will displace the same amount of air. to finish off the port displacement you need to look at the teal and violet pieces. the difference in displacement ends up being 0.008 ft^3 (due to the wood used to make the port). which is pretty negligiable.

BUT:

a 180 degree turn is gonna cause a lot more turbulence than a 90 degree turn. and therefore increase the chance of port noise. most people that do labyrinths use rouned edges and 45's in the corners to help ease airflow.

a straight port isn't going to save you much more space (if any) and i don't see how you plan on getting a large (port are) straight port to fit into the same box that you're using a labyrinth in now.

 
dimensions right now is :

Gross(inside)

width: 37(35.5)

height: 15(13.5)

depth: 23(21.5)

with 43.75" of port length.

67.5sq inch of port

makes 4cu.ft@30hz

straight port

add 1" to the width

and I can squeeze out

4.5cu.ft@31hz w/67.5sq inch

...

w/81sq inch

I can do 4.2cu.ft but @ 35hz

 
when calculating port area dont go beyond the nesesary going 10% bigger is cool. but anything bigger, it just a waist, since that will mean that youll need a longer port and it will need a bigger enclosure to fit it.

so just go big enogh to not have port noise +10% to stay safe. and you should be good to go.

anything bigger is just a waist of wood and space.

 
Activity
No one is currently typing a reply...
Old Thread: Please note, there have been no replies in this thread for over 3 years!
Content in this thread may no longer be relevant.
Perhaps it would be better to start a new thread instead.

About this thread

SQBubble

10+ year member
CarAudio.com Elite
Thread starter
SQBubble
Joined
Location
MTL
Start date
Participants
Who Replied
Replies
25
Views
1,213
Last reply date
Last reply from
PowerNaudio
IMG_20260516_193114554_HDR.jpg

sherbanater

    May 16, 2026
  • 0
  • 0
IMG_20260516_192955471_HDR.jpg

sherbanater

    May 16, 2026
  • 0
  • 0

New threads

Top