Dowel rod displacement

[UhOh Spaghetioz 10+ year member]

To find the displacement of a 1" dowel thats 12" long is the formula 1x3.14x12 /1728?

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[Kangaroux 5,000+ posts]

pi r ^2, the radius of a dowel with a 1" diameter is .5".

3.14 * (0.5)^2 * 12

or

3.14 * 0.25 * 12

or

3.14 * 3 = 9.42

9.42 / 1728 = 0.005 in^3

 

[quackhead 10+ year member]

Area of a circle = diameter x diameter x .7854

1" * 1" * .7854 = .7854

.7854 * 12 = 9.4248

9.4248 / 1728 = .0054 ft^3