Connection of a Mono amp

[JoseMCeee 10+ year member]

Ok so i got the whole idea down on how to connect the subs together and get a final impedance that will work. So now I am looking at some Mono amps that put out power but into only 1 channel. But, on the amp there is still 2 sets of speaker out puts. So does this mean that it is really 2 channel? Do I wire the subs separately to each set? Or do I just wire them together and to what set of speaker outputs?

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[squeak9798 5,000+ posts]

But, on the amp there is still 2 sets of speaker out puts. So does this mean that it is really 2 channel?

No, it's still a mono amp. Those are only speaker outputs, not independent channels. Mono refers to the signal, not the number of outputs. Both "outputs" will output the exact same signal, and there is no way around it, hence mono amp.

And the outputs are usually wired together internally in the amp; so for example, a 2ohm load on each output would make the amp "see" a 1ohm load and output it's 1ohm power.

Do I wire the subs separately to each set? Or do I just wire them together and to what set of speaker outputs?

You can wire one sub to each output. That's why they are there, to make wiring easier.

 

[JoseMCeee 10+ year member]

Ok but the amp I am lookin at puts out the watts i want into 2 ohm. But to get a final impedance of 2ohms of (2) 2ohm speakers I have to wire them together. So could i just wire both of the subs to just one output in order to get the amount watts that i want? //content.invisioncic.com/y282845/emoticons/confused.gif.e820e0216602db4765798ac39d28caa9.gif

 

[squeak9798 5,000+ posts]

With two 2ohm speakers, you can not get a final load of 2ohm. You either need a different amp or different subs. Now, if those are dual voice coil speakers and 2ohm per coil, then you need to wire them in series-parallel and put them on a single output. If those are dual voice coil subs, 4ohm per coil, you're screwed again.

 

[JoseMCeee 10+ year member]

no its 2ohm per coil. DVCS

 

[squeak9798 5,000+ posts]

Wait a minute....I'm retarded //content.invisioncic.com/y282845/emoticons/frown.gif.a3531fa0534503350665a1e957861287.gif Just wire the coils in series (so that each sub is a 4ohm load) and you can wire one to each output (because then the amp would "see" a 2ohm load). Makes the wiring a little easier //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 

[JoseMCeee 10+ year member]

ok so if i wire each sub (separatly) into 4 ohms each, Then connect each sub which is at a final of 4 ohms each, into each separate channel, the amp would have final impedance of 2ohm and put out 1200 watts rms total?

 

[qtipextra 5,000+ posts]

U Got It!

 

[JoseMCeee 10+ year member]

//content.invisioncic.com/y282845/emoticons/wowflash.gif.89a61f4caede63a11dac36e97d61323e.gif Thats kinda of confusing but if it works it works. I just never knew that 4 ohms + 4ohms= 2ohms. Kinda weird.

 

[n2audio 5,000+ posts]

//content.invisioncic.com/y282845/emoticons/wowflash.gif.89a61f4caede63a11dac36e97d61323e.gif Thats kinda of confusing but if it works it works. I just never knew that 4 ohms + 4ohms= 2ohms. Kinda weird.

What you're doing is wiring the coils parallel.

The formula for that:

1/(1/R1+1/R2+1/R3...) = Rtotal

in your case 1/(1/4+1/4) = 1/(2/4) = 4/2 = 2

Or if all the R values are equal it's just:

Rvalue/Rnumber

in your case Rvalue = 4 ohms, Rnumber = 2 ohms, 4/2 = 2

It's when you wire in series that resistances (or impedances) are just additive.

Rtotal = R1 + R2 + R3...

 

[btnhfan 5,000+ posts]

I have the same kind of question. I have 2 outputs and 2 4 ohm dvc subs. Do I wire each to 2 ohms then the amp bridges it internally to 1 ohm?

 

[JoseMCeee 10+ year member]

So the amp just bridges them internally? Cuz I looked at the diagrams of connecting 2 subs togther and it would be the exact same thing if the amp would just put the two negs toghether and the tow pos together inside the amp

 

[n2audio 5,000+ posts]

So the amp just bridges them internally?

No, the two sets of speaker outputs are parallel inside the amp. It has nothing to do with bridging.