You are all right and you are all wrong... //content.invisioncic.com/y282845/emoticons/fyi.gif.9f1f679348da7204ce960cfc74bca8e0.gif
I agree 99.9% of the time people use Capacitors for the wrong reasons and don't really need them...
They are meant for 'stiffening' ie for short (VERY SHORT) impulse voltage drop issues.
Also, a battery only produces its own charge for a very short period. If batteries generated their own power by under going a great chemical reaction then we wouldn't need to charge them. //content.invisioncic.com/y282845/emoticons/wink.gif.608e3ea05f1a9f98611af0861652f8fb.gif
Go to this link...
http://falstad.com/circuit/
Import this data in the import menu under file.
$ 13 5.0E-6 30.96768661252054 30 5.0 50
v 64 320 64 192 0 0 40.0 14.0 0.0
r 144 144 144 224 0 5.1228
d 144 224 144 288 0
d 144 288 144 352 0
w 64 192 64 112 0
w 64 112 144 112 0
w 144 112 144 144 0
w 64 320 64 368 0
w 64 368 144 368 0
w 144 368 144 352 0
t 144 224 192 224 0 1 0.7888489281771617 0.7891001865734992
r 192 240 192 368 0 7.0E-4
w 144 368 192 368 0
p 192 112 192 208 0
w 192 208 224 208 0
w 224 208 224 368 0
w 224 368 256 368 0
c 336 144 336 272 0 100.0 13.993927120418611
c 480 144 480 272 0 1.0 13.997831899442744
r 560 144 560 272 0 0.05
r 336 272 336 288 0 0.0010
r 384 272 384 288 0 0.0010
r 480 272 480 288 0 1.0E-4
w 560 112 560 144 0
w 336 288 336 368 0
w 384 368 336 368 0
w 480 288 480 368 0
w 480 368 384 368 0
w 560 272 560 368 0
w 560 368 480 368 0
s 384 112 480 112 0 false false
s 336 112 384 112 0 false false
s 256 112 336 112 0 false false
s 336 144 336 112 0 true false
s 384 144 384 112 0 true false
s 480 144 480 112 0 true false
p 256 112 256 368 0
w 256 368 336 368 0
w 384 368 384 288 0
w 144 112 192 112 0
S 192 112 192 64 0 true false 0
r 208 64 256 64 0 0.0025
w 256 64 256 112 0
c 384 144 384 272 0 100.0 13.994026263554805
s 480 112 560 112 0 true true
o 0 64 0 2 20.0 1.6 0
o 17 64 0 2 20.0 9.765625E-5 1
o 17 64 0 1 10.0 9.765625E-5 1
o 43 64 0 2 20.0 9.765625E-5 2
o 43 64 0 1 10.0 9.765625E-5 2
o 18 64 0 2 20.0 9.765625E-5 3
o 18 64 0 1 10.0 9.765625E-5 3
o 32 64 0 1 7.62939453125E-5 9.765625E-5 4
o 19 64 0 2 7.62939453125E-5 9.765625E-5 5
o 19 64 0 1 7.62939453125E-5 9.765625E-5 5
o 36 64 0 2 20.0 9.765625E-5 6
Play with it a little bit. Especially with short impulses on the loads. (CLICK ON THE SWITCH TO CONNECT/DISCONNECT)
(BTW, these numbers are just set up to show my point and that is it.)
Basically... The current limiter circuit simulates a 250 Ampere alternator. The 100F Capacitors with the 1m Ohm resistors act like batteries (so to speak). The small capacitor acts like a normal capacitor with a much lower resistance and a quicker load reaction time than the battery.
Here are the steps to figuring out this stupid question.
1) Disconnect all the caps and batteries so you can only run on the alt. Click the load on and off several times and watch what happens to the voltage and the current.
-What you find is a instant voltage drop because of the load change and a pull of 250 ampere on the alt.
2)Connect only the capacitor. Test under load.
-What you will find is a slight 'stiffening' for short impulse loads. If you do this step correctly you will find that during short impulses the capacitor reacts to the change in load and the alt will not pull 250 amperes. However, if you leave it on long enough the capacitor will no longer be of no extra help.
3) Connect the one of the batteries. And test under load.
-You will find a much increased stability in the voltage. But, if you disconnect the capacitor you will find an increase in the current sent form the alternator.
4) Connect the other battery. Test.
I am not trying to say that all you need in your system is a capacitor. BUT, what I am trying to show here is that there is some benefit in some applications where an amplifier requires high current for quick impulse signals.