anyone good at Curve Sketching?

[hrtbrk1 5,000+ posts]

i hate calculus and i haven't been paying attention in class...was wondering if anyone can help me out...with a few problems...how do u find the y and x intercepts and whatnot? also heres one problem

y=2x^5-5x^2+1

its asking for intercepts, domain, local min and max, inflection pt, concavity, and graph

Click to read more...

 

[cman9012 10+ year member]

Been awhile since I've taken any math but cant you type it into the y= graph on your calculator to get the intercepts, domain, local min and max, and the graph? I don't know how to get inflection or concavity.

 

[hrtbrk1 5,000+ posts]

i cant use a calc...were not allowed

 

[cman9012 10+ year member]

Alright sorry man I stopped taking math before I got to cal. I was suppose to take it my senior year in high school but didn't lol. Good luck.

 

[hrtbrk1 5,000+ posts]

lol...this sucks...

 

[bhsdriller 10+ year member]

Should of paid attention in class, sucks for you. We just got done with that section

 

[hrtbrk1 5,000+ posts]

help a brotha out

 

[bhsdriller 10+ year member]

Let me look back at my notes and see if I can put something together

 

[akizzle 10+ year member]

this might help http://calc101.com/webMathematica/sketch.jsp

 

[hrtbrk1 5,000+ posts]

i gotta show my work

 

[GearGuy2001 10+ year member]

i gotta show my work

Dam your F*cked

 

[cobra65427289 10+ year member]

Haha! go through it and find the first derivative, then the second. Find critical numbers by setting derivative equal to zero. Using the critical numbers, form intervals and test integers on that in the first derivative to come up with whether the curve is rising or falling, use the intervals on the second derivative to give you concave up or down. A positive answer in the derivative will yield an upward slope, and a positive in the second derivative will yield a concave up. Just as a negative will yield a negative slope and a concave down curve, respectively.

Do your own work from there on out, it isn't that hard. All that material should have been covered in chapters 1-3 of your calc book.

 

[hrtbrk1 5,000+ posts]

chapter 4 actually

 

[hrtbrk1 5,000+ posts]

Haha! go through it and find the first derivative, then the second. Find critical numbers by setting derivative equal to zero. Using the critical numbers, form intervals and test integers on that in the first derivative to come up with whether the curve is rising or falling, use the intervals on the second derivative to give you concave up or down. A positive answer in the derivative will yield an upward slope, and a positive in the second derivative will yield a concave up. Just as a negative will yield a negative slope and a concave down curve, respectively.
Do your own work from there on out, it isn't that hard. All that material should have been covered in chapters 1-3 of your calc book.

what about inflection points?

 

[cobra65427289 10+ year member]

what about inflection points?

Set the second derivative equal to zero. Test the numbers you come up with based on those intervals to find concavity, if concavity changes from one interval to the next, that is a point of inflection.