aeroports vs slot port

[king ranch 5,000+ posts]

not sure yet i am going to just get a general idea of the box and everything and go from there when i get the subs and amp in my hand havent even ordered them yet

 

[Lakota 5,000+ posts]

could one of you guys that have been answering everything so far answer the last questions i have
thanks

Be patient, it's a message board not a chat room 3 4" should work fine. You may even bump that tuning a tad bit higher to 35hz or so if you wish(that's the area I prefer for daily) and the port length will decrease a little bit. Volume = LxWxH. Area of a circle = (pi)(radius)^2. Multiply that area you get (should be 12.xx) by the height and you have the approx. volume of the port.

 

[JimJ 5,000+ posts]

so when the hell will this box be given the go ahead to actually get built?

He builds boxes on my schedule...I bought my drivers in April, it's now January and I'm just getting ready to put the first coat of stain on the enclosures //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif

 

[btdickey99 5,000+ posts]

He builds boxes on my schedule...I bought my drivers in April, it's now January and I'm just getting ready to put the first coat of stain on the enclosures //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif

lol are you his daddy??

I just ask bc there are about 5 threads out on this subject and seems to be anxious, and has had like 3 diff boxes designed....just wont pull the trigger for the build

 

[king ranch 5,000+ posts]

Be patient, it's a message board not a chat room 3 4" should work fine. You may even bump that tuning a tad bit higher to 35hz or so if you wish(that's the area I prefer for daily) and the port length will decrease a little bit. Volume = LxWxH. Area of a circle = (pi)(radius)^2. Multiply that area you get (should be 12.xx) by the height and you have the approx. volume of the port.

is that the height of the box or is that supposed to be length i am confused

 

[BuckyBoy 10+ year member]

For 3 4"x14.5" ports tuning @ 35Hz the port displacement is .32ft^3

For 3 4"x16.75" ports tuning @ 33Hz the port displacement is .37ft^3

Add whichever of those to your subs displacement.

Then, add that to 5. And that is what you internal volume should be.

 

[king ranch 5,000+ posts]

15.5 x 23.5 x 27.5= 5.796 internal

mins .20 for both sub displacement and .37 for aero space

equals 5.22 for subs and comes out to 2.6 per sub

that should be the final dimensions correct

well i have to go to bed i have school tommorow so i will talk to you on bulding me a box like that and prices and everything

 

[BuckyBoy 10+ year member]

15.5 x 23.5 x 27.5= 5.796 internalmins .20 for both sub displacement and .37 for aero space

equals 5.22 for subs and comes out to 2.6 per sub

that should be the final dimensions correct

well i have to go to bed i have school tommorow so i will talk to you on bulding me a box like that and prices and everything

Looks good to me. //content.invisioncic.com/y282845/emoticons/smile.gif.1ebc41e1811405b213edfc4622c41e27.gif

 

[nineballsafety8 10+ year member]

alright... since nobody has put it out there yet... just a little math tutorial for the OP

since you know how to get your box volume.. i will give you a little help with port area and port displacement.

area of a circle (port in this case)=piR^2

where as pi is a mathematical constand roughly equal to 3.14159

R= the radius of your port (half the diameter)...

so you take your radius and multiply it by itself and then multiply that answer by pi.

as an example a 4 in port

half of 4 is 2... so u take 2 and multiply it by itself and get 4... times pi (3.14159)=12.56636

so that is the area of a standard 4 inch round port... to get port displacement you take the area (which you just found out) and multiply it by the length of the port.

now i know the math is different for area of an aero... but this is just a little insight on how shit works.

also....

in my personal opinion, givin the equipment you are talking about using and the space you are allowing for your enclosure... with a little bit of time from a box designer (i recommend IONSQL or JBLCAMRY) an isobaric single reflex bandpass with a down firing port will give you alot better performance in your application... just my opinion though.

 

[nineballsafety8 10+ year member]

oh yeah the above math gives you cubic inches... so just divide your displacement by 1728 to get cubic feet

 

[king ranch 5,000+ posts]

ok not sure what type of box you are explaning could you give me better details and pics

and why it would work better

 

[chillin 10+ year member]

good explanation nine.

I was just going to suggest googling Cylinder Volume

 

[nineballsafety8 10+ year member]

a single reflex bandpass is a sealed box inside a ported box...

isobaric loading is where you mount your drivers face to face with one wired 180 degrees out of phase... what this does for you is it divides the VAS of the drivers in half...

so essentially you can run 2 subs in half the space you would normally be able to run one in...

take ported for example... a normal volume for a single 12 is like 2.5 cubes...

but if you run 2 isobaric you could get 2 of them in 1.25... make sense?

the only draw back is you only utitlize the cone area of one driver... so you are pretty much making 2 subs into one BADASS small box sub.

lets you make your enclosure ALOT more efficient in given space and utilize the same amount of power

 

[nineballsafety8 10+ year member]

i would post some pics but am at work and everything is blocked

 

[king ranch 5,000+ posts]

ok well i have enough room to do 5.2net so it would be like a 2.6 for both subs and would tht be louder than what i have planned on doing

and which going with that kind of box is it possible to get 4 12's in my room i have

17wide 30 tall and 26 long