? about impedance

ok bro. here is the formula

= .16 ohms

2//2 = 1 so 2 // 2 // 2 = the lower number. Your probly not going to find an amp that can go that low.

So you need to wire them in series at 6ohms...

 
ok bro. here is the formula
= .16 ohms

2//2 = 1 so 2 // 2 // 2 = the lower number. Your probly not going to find an amp that can go that low.

So you need to wire them in series at 6ohms...
Not quite.

Three SVC2ohm subs will give you either .66 or 6ohm final load.

An easy way to do it is (ohm load for each sub/number of subs), so 2/3 in this case, or .66ohms.

 
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