9.1 and W7

[ScooobyDoo11 10+ year member]

I recently bought a 10 w7 and jl 500/1 but the 500/1 turned out to be bad. I already have a 9.1 laying around and I was wondering if it would be ok to run it at 3-ohm and how much power would it be putting out? Thanks.

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[Worlddre 5,000+ posts]

im gonna guess somewhere between 650 and 700

 

[squeak9798 5,000+ posts]

Yes, 3ohm would be fine.

Going off of rated power, it should be somewhere in the neighborhood of 600w. But, those amplifiers are supposed to be underrated.

 

[ScooobyDoo11 10+ year member]

Thanks for the quick replies. So the 9.1 should experience any problems? Cuz if not then I will just leave it hooked to the w7 and just get the money back for the 500/1 instead of a replacement. If not then of course I will get me a 500/1. Thanks again.

 

[squeak9798 5,000+ posts]

There's no reason it should.

The amplifier is 1ohm stable. It should therefore drive your 3ohm subwoofer with no problems at all.

 

[HardHitter 10+ year member]

Depending on if you want the extra power or saving money, the Nine.2X actually puts out more power @3ohms than the Nine.1. The Nine.1 will put out around 650W and the Nine.2x will put out 750-800W for cheaper.

 

[DFW40 10+ year member]

Model Name : NINe.1 Class D Amplifier

RMS Power @ 12.5v : 1200 x 1 @1ohm,900 x 1 @2Ohm,450 x 1 @4Ohm

Should be 675 watts @ 3ohms with 12.5 volts so running around 13.8 volts it will see even more power, also remember that you are not really going to get that much more out of the sub, in the right box 500-600 watts is going to push the sub to its max.

 

[squeak9798 5,000+ posts]

Model Name : NINe.1 Class D AmplifierRMS Power @ 12.5v : 1200 x 1 @1ohm,900 x 1 @2Ohm,450 x 1 @4Ohm

Should be 675 watts @ 3ohms with 12.5 volts so running around 13.8 volts it will see even more power,

Based off of the power ratings, it'd be 600w @ 3ohm.

sqrt(450*4) = 42.42641

42.42641^2/3 = 600

 

[DFW40 10+ year member]

Based off of the power ratings, it'd be 600w @ 3ohm.
sqrt(450*4) = 42.42641

42.42641^2/3 = 600

I just split the difference betweet 900@2 and 450@4 and assumed it would be in the middle.

 

[helotaxi 5,000+ posts]

I just split the difference betweet 900@2 and 450@4 and assumed it would be in the middle.

It's not. Power and impedance are not linearly related.