CJL 10+ year member CarAudio.com Veteran 4,082 0 oZone Apr 9, 2006 #1 OK lets say im using a scrap piece of 3/4" MDF that is 10" H and 2" W so it would be 10 x .75 x 2 = 15 cubic inches. Is That right? Click to read more...
OK lets say im using a scrap piece of 3/4" MDF that is 10" H and 2" W so it would be 10 x .75 x 2 = 15 cubic inches. Is That right? Click to read more...
BassAce 10+ year member - 2,765 1 IN Apr 9, 2006 #2 You did the calculation right by adding all three dimensions Take that cubic inches and convert it into cubic feet, assuming you used cubic feet for your enclosure. 15/1728 = 0.00868055555555555555555555555555555555555555555556 50 decimal places for extra precision. The reason you use 1728 is because there are 1728 cubic inches in one cubic foot 12^3=1728 btw if you didn't know.
You did the calculation right by adding all three dimensions Take that cubic inches and convert it into cubic feet, assuming you used cubic feet for your enclosure. 15/1728 = 0.00868055555555555555555555555555555555555555555556 50 decimal places for extra precision. The reason you use 1728 is because there are 1728 cubic inches in one cubic foot 12^3=1728 btw if you didn't know.
OP CJL 10+ year member CarAudio.com Veteran 4,082 0 oZone Apr 9, 2006 Thread Starter #3 Ok thanks i was just making sure i know how to do it right
S ssj2xxgotenxx 10+ year member The Chan Man 2,613 0 Bay Area Apr 10, 2006 #4 Sorry to jack your thread, but it loos like you question was answered. So... How much area should you leave open for air to pass through? Is it the equvilent to the cone surface area?
Sorry to jack your thread, but it loos like you question was answered. So... How much area should you leave open for air to pass through? Is it the equvilent to the cone surface area?