How big is my load.? :D

khi
10+ year member

¤ Iñdi° Møâñin ¤
whussup?

mmm....jus wonderin...

me and ma friends were finkin...if u put a 4 ohm sub....anda 8 ohm sub...what kinda load would u get??

+ how would u go abouts wiring it?

thanx //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif

 
i once hooked up a 4ohm & 8omh sub to an amp...they were mine...the 8ohm one wouldnt even move, but the 4ohm one was slammin...then i smelt something burning and pushed on the 8ohm sub and smoke came out all around it //content.invisioncic.com/y282845/emoticons/eek.gif.771b7a90cf45cabdc554ff1121c21c4a.gif

they were only the thunder 4000's so i turned off the stereo and started laughin my *** off //content.invisioncic.com/y282845/emoticons/satan.gif.9c6a335ed7aeeed3ee273e573f1fcaac.gif , ended up going back to HH Gregg and gettin 2 brand new 8ohm 4000's for free

 
the equation for resistance in a parallel circuit is (R1xR2)/(R1+R2)=Rt --> if you wanna get the resistance for say 3 loads, do that equation for the first 2, then use the answer you get from the first 2 and use that equation again with the 3rd load/sub, or if the resistances are the same, then just take the resistance value and divide by the number or loads/subs -

equation for resistance in a series circuit is r1+r2+r3 ect...easy math :)

hope i helped somehow

-patio furniture

 
Originally posted by d audio 450 the equation for resistance in a parallel circuit is (R1xR2)/(R1+R2)=Rt --> if you wanna get the resistance for say 3 loads, do that equation for the first 2, then use the answer you get from the first 2 and use that equation again with the 3rd load/sub, or if the resistances are the same, then just take the resistance value and divide by the number or loads/subs -

 

equation for resistance in a series circuit is r1+r2+r3 ect...easy math :)

 

hope i helped somehow

-patio furniture

where are u getting 3 loads??? its an 8ohm sub and a 4ohm sub.....and your series formula seems flawed to me....cause 4ohms + 8ohms is 12 ohms.....which if they were wired in series, i'd think it would be a higher value than that......thats just the combined ohm load

and if your equation for parallel is correct then it would be a 2.6ohm load which doesnt sound right for this application...but i might be wrong.....

 
im sayin IF you had 3 loads

im sure that the equation for resistance total (Rt) in a series circuit is R1+R2+ ect=Rt

im in an EE tech course for school now- so i know it

if you wire an 8ohm sub in series with a 4, the resistance will be 12ohms total, but the voltage drops will be different for each sub, meaning they wont have the same output power

wire the 8 and 4 subs in parallel- (4x8)/(4+8)=(32)/(12)=2.66ohms

the equation (4ohms)/(# of subs)=Rt only applies when the resistances are the same, all subs must be 4ohms

i took an 8 ohm speaker, and a 4ohm sub, wired em in parallel and tested it with my good ol' radioshack multimeter- got 2.5-2.8 ohms, it kept jumpin back and forth between there

i dont wanna sound like an ***, i just wanna make sure im tellin people the right stuff and all- feel fre to pm me or email me if ya want

-pat

 
2.6ohm seems right.

wire (2) 4ohm sub together and you get 2ohm

wire a 4ohm and an 8ohm sub together and you get 2.6ohm

since (2) 4ohm subs are wired in parallel to get 2ohm, raising R1 or R2 impedence would raise the total impedence also, and thats what happened with the 4ohm and 8ohm.. it seems right.

this equation works only in parallel though. (i hope it only does:D )

 
well looking back; it does actually make sense.....i was having one of those days where my brain wasnt working earlier todfay when i posted that...heh....thanks for clearing everything up for everyone

 
Originally posted by Goddyd4me well looking back; it does actually make sense.....i was having one of those days where my brain wasnt working earlier todfay when i posted that...heh....thanks for clearing everything up for everyone
but off topic here..but how does your road gear speaker sound? better than stock?:p //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif

 
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