Calc 2 Question

[RKPsk8er 10+ year member]

This is the problem. I need to know if it converges or diverges using the integral test. I don't know how to integrate this. My guess is a u substitution of ln.

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[Bobby322 10+ year member]

What's that?

 

[galacticmonkey 5,000+ posts]

You people and your voodoo magic. //content.invisioncic.com/y282845/emoticons/frown.gif.a3531fa0534503350665a1e957861287.gif

 

[RKPsk8er 10+ year member]

You people and your voodoo magic. //content.invisioncic.com/y282845/emoticons/frown.gif.a3531fa0534503350665a1e957861287.gif

wish my calculator had a **** you button.

 

[bw_audio 10+ year member]

..

 

[AlterEgo99 5,000+ posts]

This is the problem. I need to know if it converges or diverges using the integral test. I don't know how to integrate this. My guess is a u substitution of ln.

Don't post shit like that OP! You'll scare the CA kiddies!!! //content.invisioncic.com/y282845/emoticons/eek.gif.771b7a90cf45cabdc554ff1121c21c4a.gif

 

[RKPsk8er 10+ year member]

 

[AlterEgo99 5,000+ posts]

//content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif Felt the same way in a calculus class during my Master's //content.invisioncic.com/y282845/emoticons/biggrin.gif.d71a5d36fcbab170f2364c9f2e3946cb.gif

 

[JBGabriel 10+ year member]

Whats your major?

 

[pilyin 10+ year member]

I don't remember this stuff real well, and don't feel like looking up the log rules but you might try splitting it (1/n) * (1/ln) and working from there.

 

[Trey803 5,000+ posts]

converges to zero according to maple. It is also showing 1/n*ln....as being the same as ln/n. I just used a limit to get this answer not the integral test. I'm not sure how to do it that way. Wouldn't this be an inproper integral since the upper bound is infinity? If so the integral is going to become a limit anyways.

 

[RKPsk8er 10+ year member]

I don't remember this stuff real well, and don't feel like looking up the log rules but you might try splitting it (1/n) * (1/ln) and working from there.

I set u = to ln

du=1/n dn

that gave me integral(1/u)du

that came out to ln(ln) 2 to infinity or t once you switch the improper integral to a limit.

does that look okay?

 

[RKPsk8er 10+ year member]

the integral test works if the series is positive, continuous and decreasing. It looks like all that is true, and my proffesor asked us to solve using the integral test so I'd assume so. Basically if the integral of An converges/diverges, so does the series. I'll put a pic of my work for someone to check.

 

[iknownothin2006 10+ year member]

ahhhhhhhhhhhh i hated calc 2 had similar problem on a test let me find that

 

[RKPsk8er 10+ year member]

ahhhhhhhhhhhh i hated calc 2 had similar problem on a test let me find that

thanks. im about to post up what I got.