H Hjbennett 10+ year member Member 117 0 Yazoo city, MS May 2, 2013 #1 Can someone tell me the area of this enclosure? And also can you tell me the depth changes needed for 2.2 cu ft? Thanks for any help you can offer. Click to read more...
Can someone tell me the area of this enclosure? And also can you tell me the depth changes needed for 2.2 cu ft? Thanks for any help you can offer. Click to read more...
OP H Hjbennett 10+ year member Member 117 0 Yazoo city, MS May 3, 2013 Thread Starter #2 Bump up. Anyone? Please
mylows10 5,000+ posts B2,singer,ampere rep 22,678 76 monterey , ca May 3, 2013 #3 ok henry you need 14 x 28 x 18 for the box port 2.75 x 30 to net what you need for a xfl 12
fasfocus00 5,000+ posts doITdaWHITEwayORdoITtwice 5,712 58 New Orleans, LA May 3, 2013 #4 length x width = square inches length x width x height = cubic inches cubice inches / 1728 = cubic feet
length x width = square inches length x width x height = cubic inches cubice inches / 1728 = cubic feet
OP H Hjbennett 10+ year member Member 117 0 Yazoo city, MS May 3, 2013 Thread Starter #5 My lows that would be 4 cu ft? Thought 2.2 for xfl. Have to rethink my enclosure for that
OP H Hjbennett 10+ year member Member 117 0 Yazoo city, MS May 4, 2013 Thread Starter #6 @mylows10 lol i unno how that works Last edited by a moderator: May 4, 2013
mylows10 5,000+ posts B2,singer,ampere rep 22,678 76 monterey , ca May 4, 2013 #7 Internal after port displacement it's 2.2 cubic ft
OP H Hjbennett 10+ year member Member 117 0 Yazoo city, MS May 4, 2013 Thread Starter #8 Due to trunk space i have to use an offset "triangular" shape. If i lengthen bottom depth i Can shorten top and still get same volume.
Due to trunk space i have to use an offset "triangular" shape. If i lengthen bottom depth i Can shorten top and still get same volume.