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Understanding series/parallel help please
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<blockquote data-quote="helotaxi" data-source="post: 4812726" data-attributes="member: 550915"><p>Once again you've missed/neglected Ohm's law. You can't apply different voltages to two wires of the same resistance and get the same power through each. The voltage determines the current and the current multiplied by the voltage is the power lost.</p><p></p><p>Regardless of how the whole thing is wired up, if you have two subs wired to the same final impedance on identical amps they will both see the same amount of power and they will need to shed the same amount of heat. The same amount of voltage is applied to each driver, inducing the same current and thus dropping the same amount of power. It IS really easy to understand, and I haven't confused the topic at all, you just haven't put the pieces together.</p><p></p><p>Think about it. P=I^2 * R. If you have a lower resistance/impedance, you can run more current for the same power loss. Current isn't the only variable like you're treating it. You're tying to change only one of the variables and keep the result the same, it doesn't work that way. Yes there would be more current through each coil with a D1 sub wired in series vs a D4 in parallel, but because of the lower impedance, the you can run more current for the same power, change one variable and you have to change the other to keep result constant which we've stated is the case.</p></blockquote><p></p>
[QUOTE="helotaxi, post: 4812726, member: 550915"] Once again you've missed/neglected Ohm's law. You can't apply different voltages to two wires of the same resistance and get the same power through each. The voltage determines the current and the current multiplied by the voltage is the power lost. Regardless of how the whole thing is wired up, if you have two subs wired to the same final impedance on identical amps they will both see the same amount of power and they will need to shed the same amount of heat. The same amount of voltage is applied to each driver, inducing the same current and thus dropping the same amount of power. It IS really easy to understand, and I haven't confused the topic at all, you just haven't put the pieces together. Think about it. P=I^2 * R. If you have a lower resistance/impedance, you can run more current for the same power loss. Current isn't the only variable like you're treating it. You're tying to change only one of the variables and keep the result the same, it doesn't work that way. Yes there would be more current through each coil with a D1 sub wired in series vs a D4 in parallel, but because of the lower impedance, the you can run more current for the same power, change one variable and you have to change the other to keep result constant which we've stated is the case. [/QUOTE]
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