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<blockquote data-quote="Papermaker85" data-source="post: 8486177" data-attributes="member: 572595"><p>wew lad, you cannot simply state that. you have to know the amperage of the load.</p><p></p><p>@ 1ohm 3000 RMS. amperage^2*impedance is wattage.. so about 53 amps. 14 or 12 under NEC code ist rated for anywhere CLOSE to that.</p><p></p><p>with a amberiant tempature of less than 120 degrees a single conductor freeair <a href="http:////forums/usertag.php?do=list&amp;action=hash&amp;hash=8" target="_blank">#8</a> is rater for 55 amps. that is with less tha a 5% in voltage drop/loss.</p></blockquote><p></p>
[QUOTE="Papermaker85, post: 8486177, member: 572595"] wew lad, you cannot simply state that. you have to know the amperage of the load. @ 1ohm 3000 RMS. amperage^2*impedance is wattage.. so about 53 amps. 14 or 12 under NEC code ist rated for anywhere CLOSE to that. with a amberiant tempature of less than 120 degrees a single conductor freeair [URL="http:////forums/usertag.php?do=list&action=hash&hash=8"]#8[/URL] is rater for 55 amps. that is with less tha a 5% in voltage drop/loss. [/QUOTE]
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