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Port walls?
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<blockquote data-quote="DNick454" data-source="post: 6503603" data-attributes="member: 600755"><p>Yeah, you don't get port area by multiplying it by the actual length of the port's path. It's cross-sectional area. How tall the port is by how wide is port area. The bigger the port area is, the LONGER it actually has to be to achieve the same tuning. But, you can't have it too small in port area or it will be like breathing through a straw and the air velocity coming out of the port will be excessive and you will get turbulence and port noise.</p><p></p><p>1.5" wide X 17.5" tall = 26.25 sq in of port <em>area</em>. 26.25 sq in divided by 2 cubes = 13 sq in per cubic foot of net volume which is actually ok.</p></blockquote><p></p>
[QUOTE="DNick454, post: 6503603, member: 600755"] Yeah, you don't get port area by multiplying it by the actual length of the port's path. It's cross-sectional area. How tall the port is by how wide is port area. The bigger the port area is, the LONGER it actually has to be to achieve the same tuning. But, you can't have it too small in port area or it will be like breathing through a straw and the air velocity coming out of the port will be excessive and you will get turbulence and port noise. 1.5" wide X 17.5" tall = 26.25 sq in of port [I]area[/I]. 26.25 sq in divided by 2 cubes = 13 sq in per cubic foot of net volume which is actually ok. [/QUOTE]
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