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<blockquote data-quote="helotaxi" data-source="post: 1785179" data-attributes="member: 550915"><p>Force has nothing at all to do with frequency response. It only has to do with efficiency. Smaller drivers are used for higher frequencies because larger drivers will start to resonate and generate high order harmonice distortion as the cone flexes. If you take 2 subs with the same motor assembly (the older RE XXX line is a good example), one a 10 and one a 15 what will be the difference in response on the high end? The 15 will probably exhibit a bit of audible breakup in the upper midbass range and the 10 will exhibit breakup at a slightly higher frequency. In both cases they breakup is a result of cone flex. The actual natural rolloff freq for both drivers will be the same though.</p><p></p><p>A smaller lighter cone will require less force to move, true. But transient response is not a function of how far the cone moves or how fast it moves. It is only a function of how fast it can change direction. Resistance to change in current direction (current provides the motive force to move a driver and the change in that current is what determines the frequency played) is called inductance. The lower the inductance, the less resistant the voicecoil is to reversals in current flow and the higher a frequency it can play. Driver efficiency is affected by moving mass and the strength of the motor assembly. A strong motor can accelerate a cone more quickly, but all that means is the cone moves farther on each cycle and moves faster as a result. A heavier moving assemlbly will not affect how fast the cone changes direction, only how far it moves on each cycle. Therefore an 8" sub with the same motor as a 12" sub will move farther and accelerate faster than the 12, but they will be able to play the same higher freqs. The difference is just that the 12 won't move as far on each cycle. Large heavy coned drivers don't play higher freqs well becuase they inherently have high inductance voicecoils to move the heavy cone and coil. The inductance causes the high freq rolloff, the cone size and mass only affect efficiency.</p><p></p><p>If you want the physics equations, I can explain in more detail.</p><p></p><p>General rules are generally wrong.</p></blockquote><p></p>
[QUOTE="helotaxi, post: 1785179, member: 550915"] Force has nothing at all to do with frequency response. It only has to do with efficiency. Smaller drivers are used for higher frequencies because larger drivers will start to resonate and generate high order harmonice distortion as the cone flexes. If you take 2 subs with the same motor assembly (the older RE XXX line is a good example), one a 10 and one a 15 what will be the difference in response on the high end? The 15 will probably exhibit a bit of audible breakup in the upper midbass range and the 10 will exhibit breakup at a slightly higher frequency. In both cases they breakup is a result of cone flex. The actual natural rolloff freq for both drivers will be the same though. A smaller lighter cone will require less force to move, true. But transient response is not a function of how far the cone moves or how fast it moves. It is only a function of how fast it can change direction. Resistance to change in current direction (current provides the motive force to move a driver and the change in that current is what determines the frequency played) is called inductance. The lower the inductance, the less resistant the voicecoil is to reversals in current flow and the higher a frequency it can play. Driver efficiency is affected by moving mass and the strength of the motor assembly. A strong motor can accelerate a cone more quickly, but all that means is the cone moves farther on each cycle and moves faster as a result. A heavier moving assemlbly will not affect how fast the cone changes direction, only how far it moves on each cycle. Therefore an 8" sub with the same motor as a 12" sub will move farther and accelerate faster than the 12, but they will be able to play the same higher freqs. The difference is just that the 12 won't move as far on each cycle. Large heavy coned drivers don't play higher freqs well becuase they inherently have high inductance voicecoils to move the heavy cone and coil. The inductance causes the high freq rolloff, the cone size and mass only affect efficiency. If you want the physics equations, I can explain in more detail. General rules are generally wrong. [/QUOTE]
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