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<blockquote data-quote="shredder1" data-source="post: 8575366" data-attributes="member: 658920"><p>Well... After a good nights sleep... I&#039;ve decided to try this... I was VERY confused as well until I noticed something... Let&#039;s try...I am doing this from memory now as the link won&#039;t work anymore unless I sign up... OK... how do you find the area of a circle? radius squared X pi = area... correct? so an 8&quot; is 16 x 3.14 = 50.24 1n2 easy. We all know how to figure that. The next part however is what stumped me . The tutorial said to find the minimum clearance to the rear wall that the equation is 2pi x radius x height. There is only one variable here and that is the clearance to the rear wall as 2pi will always be 3.14+3.14... OK so 6.28 x radius is next and we know our radius is 4 so... 6.24 x 4 = 24.96... Now here comes the part that threw me... you need to find&nbsp; the last variable... the height.&nbsp; So... 2pi x radius is 24.96 in2 and what number multiplies by this to get the area of 50.24 in2 ?.. I&#039;m getting 2.0128... now unless your using a micrometer thats 2&quot; clearance. Now you need to find the clearance that you need from the inner port to the outer port and that&#039;s easy because&nbsp; we know the area of your 8&quot; port is 50.24 in2 so... I&#039;d account for the port material displacement as well if your using 1/4&quot; wall PVC so the area of the inner port displacement here is now 56.716 in2 but whatever size pipe your using for the outer port must be oversize by 50.24 in2. So port area with port wall is 56.7 in2, port area needed is 50.24 in2 so add them up. 50.24 + 56.7 = 106.94.So the outer port needs to have an inner area of 106.94 in2. After a few tries I came up with 11.75&quot; ID port as the outer. Lets check... the radius is 5.875 so using pi x radius2 = area I get 108.37 in2 now subtract the inner port with wall number which will be 108.37 in2 - 56.7 in2 = 51.67 in2. That&#039;s as close as I could get it and a lot more accurate than last time as I DID account for the material. I&#039;m guessing that being off by an square inch won&#039;t matter. Hope this helps!</p></blockquote><p></p>

[QUOTE="shredder1, post: 8575366, member: 658920"] Well... After a good nights sleep... I've decided to try this... I was VERY confused as well until I noticed something... Let's try...I am doing this from memory now as the link won't work anymore unless I sign up... OK... how do you find the area of a circle? radius squared X pi = area... correct? so an 8" is 16 x 3.14 = 50.24 1n2 easy. We all know how to figure that. The next part however is what stumped me . The tutorial said to find the minimum clearance to the rear wall that the equation is 2pi x radius x height. There is only one variable here and that is the clearance to the rear wall as 2pi will always be 3.14+3.14... OK so 6.28 x radius is next and we know our radius is 4 so... 6.24 x 4 = 24.96... Now here comes the part that threw me... you need to find the last variable... the height. So... 2pi x radius is 24.96 in2 and what number multiplies by this to get the area of 50.24 in2 ?.. I'm getting 2.0128... now unless your using a micrometer thats 2" clearance. Now you need to find the clearance that you need from the inner port to the outer port and that's easy because we know the area of your 8" port is 50.24 in2 so... I'd account for the port material displacement as well if your using 1/4" wall PVC so the area of the inner port displacement here is now 56.716 in2 but whatever size pipe your using for the outer port must be oversize by 50.24 in2. So port area with port wall is 56.7 in2, port area needed is 50.24 in2 so add them up. 50.24 + 56.7 = 106.94.So the outer port needs to have an inner area of 106.94 in2. After a few tries I came up with 11.75" ID port as the outer. Lets check... the radius is 5.875 so using pi x radius2 = area I get 108.37 in2 now subtract the inner port with wall number which will be 108.37 in2 - 56.7 in2 = 51.67 in2. That's as close as I could get it and a lot more accurate than last time as I DID account for the material. I'm guessing that being off by an square inch won't matter. Hope this helps! [/QUOTE]

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