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Message: <blockquote data-quote="Trixter" data-source="post: 1619707" data-attributes="member: 542668">the piece that your adding will not be added as displacement inside the box. the port volume and the materials that it is made out of are subtracted from the box volume. the is the port's displacement. the volume of this piece does not matter and does not need to be figured or accounted for.if you have 1cu' that 12" x 12" x 12". 12x12x12=1728.when you measure you get the cu" and then divide by 1728 to get the cu'. your theory would work if you divided your numbers by 12 first and then multipled them.whatever the length is from the front to the back is what it needs to be. to me it looks like 10.25 + .75 (for the rear port wall section) and another .75 (to make it flush with the front of the box.</blockquote>

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