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<blockquote data-quote="helotaxi" data-source="post: 4960022" data-attributes="member: 550915">Your &quot;formula&quot; works (very roughly) only by sheer luck and only at approximately 70% efficiency.&nbsp; I&#039;d like you to explain how it has any basis in Ohm&#039;s Law.I come up with 119A at 12V and 70% efficiency using the actual formula.&nbsp; The problem with your method is that it simply doesn&#039;t apply the concept of efficiency correctly.&nbsp; You&#039;re multiplying by the efficiency once you have a current number based on 50% efficiency.&nbsp; By your method, current draw will decrease as efficiency decreases...that fits how?&nbsp; By your method current draw at 60% efficiency would be 100A.&nbsp; The correct answer would be 139A.&nbsp; That&#039;s not even close.That is also an almost 20A difference in max current draw between 60 and 70% efficiency.&nbsp; That&#039;s a pretty big difference.&nbsp; I realize that it won&#039;t make that much difference under normal use, but it&#039;s still hardly insignificant.Your team made some great amps, I have a few myself, but that doesn&#039;t erase the fact that your logic is flawed.edit: and me personally, I don&#039;t really care how much current it might draw on the bench cause I don&#039;t listen to the amp there, nor do I have a use for 1000W.&nbsp; Efficiency still matters because under any conditions, more efficient means less current regardless of power level or whether we&#039;re talking on the bench or in the car.</blockquote>

[QUOTE="helotaxi, post: 4960022, member: 550915"] Your "formula" works (very roughly) only by sheer luck and only at approximately 70% efficiency. I'd like you to explain how it has any basis in Ohm's Law. I come up with 119A at 12V and 70% efficiency using the actual formula. The problem with your method is that it simply doesn't apply the concept of efficiency correctly. You're multiplying by the efficiency once you have a current number based on 50% efficiency. By your method, current draw will decrease as efficiency decreases...that fits how? By your method current draw at 60% efficiency would be 100A. The correct answer would be 139A. That's not even close. That is also an almost 20A difference in max current draw between 60 and 70% efficiency. That's a pretty big difference. I realize that it won't make that much difference under normal use, but it's still hardly insignificant. Your team made some great amps, I have a few myself, but that doesn't erase the fact that your logic is flawed. edit: and me personally, I don't really care how much current it might draw on the bench cause I don't listen to the amp there, nor do I have a use for 1000W. Efficiency still matters because under any conditions, more efficient means less current regardless of power level or whether we're talking on the bench or in the car. [/QUOTE]

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