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<blockquote data-quote="hoboham" data-source="post: 6158483" data-attributes="member: 612316">so the bl will increase if ran in series,side note for the new coilB=μ0*i*n&nbsp; (for a coil)so2B=μ0*i*2nalsoΦB=B*A&nbsp;&nbsp; (magnetic flux through the central region of an inductor)again2ΦB=2B*AalsoL=μ0*n^2*l*A (n=turns/length)soμ0*(2n)^2*l*A4L=μ0*4(n^2)*l*A4L,Emf=-L*di/dtwith 4 times the inductance, as the current in the coil increases an Emf (voltage) is produced, 4 times the inductance the 4 times the Emf produced, this Emf opposes the the direction of the increasing current.this can be described as inductive reactanceXL=ωdLthis is measured in ohms, where ωd is the driving frequencyso&nbsp; 4XL=ωd4L,&nbsp; this could be good or bad depends on the frequencyall of this is dependent on the number of effective turns, running the coils in series will &quot;double&quot; the amount of turns, ran in parallel it will have the same number of effective turns as your old coil but the resistance will be half the amount cuz there is double the cross sectional area &quot;2 wires instead of 1&quot;.alsop=V^2/R (resistive dissipation)V^2/(.5*R)2p=V^2/(.5*R)half the resistance = twice the joule heat created in the same situationlol&nbsp; i got a B in phys 2</blockquote>

[QUOTE="hoboham, post: 6158483, member: 612316"] so the bl will increase if ran in series, side note for the new coil B=μ0*i*n (for a coil) so 2B=μ0*i*2n also ΦB=B*A (magnetic flux through the central region of an inductor) again 2ΦB=2B*A also L=μ0*n^2*l*A (n=turns/length) so μ0*(2n)^2*l*A 4L=μ0*4(n^2)*l*A 4L, Emf=-L*di/dt with 4 times the inductance, as the current in the coil increases an Emf (voltage) is produced, 4 times the inductance the 4 times the Emf produced, this Emf opposes the the direction of the increasing current. this can be described as inductive reactance XL=ωdL this is measured in ohms, where ωd is the driving frequency so 4XL=ωd4L, this could be good or bad depends on the frequency all of this is dependent on the number of effective turns, running the coils in series will "double" the amount of turns, ran in parallel it will have the same number of effective turns as your old coil but the resistance will be half the amount cuz there is double the cross sectional area "2 wires instead of 1". also p=V^2/R (resistive dissipation) V^2/(.5*R) 2p=V^2/(.5*R) half the resistance = twice the joule heat created in the same situation lol i got a B in phys 2 [/QUOTE]

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