13.75 x 18.512 x 15.954 ( 2.35 internal volume) why

alum10
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For some reason i keep confusing the hell outta my self.

Im plannin to build an enclosure ofr a single ten consisting of 2.35 cubic feet of internal air space. if my calculation are correct i would have 2.5 cu ft total volume.

1728 x 2.35 = 4060.8 inchses internal excluding port

12 to the third power = 1728

15.954 x 15.954 x 15.954 = 4060.8

finally to conculde an enclosre of

13.75 x 18.512 x 15 . 954 results in internal space for a 2.35 cu ft or 4060.8 cu inch enclosure. some one fix me up. I want this box to be simpler. WHOLE number instead of crazy fractions.

Would it matter if i was 1 to 2 inches off with internal volume space. WOuld it change the sound of performance from the woofer?

Thanks //content.invisioncic.com/y282845/emoticons/uhoh.gif.c07307dd22ee7e63e22fc8e9c614d1fd.gif//content.invisioncic.com/y282845/emoticons/uhoh.gif.c07307dd22ee7e63e22fc8e9c614d1fd.gif

 
If your one or two inches off of the cubic inches then no it's not really going to matter at all (say the box is actually 4002 cu inches when you designed a box for 4005 cu inches.) However lets say your only have room to build a box for 2.35 feet remember to take into account how much volume your port and speakers will displace or it will throw your tuning off.

 
yea, i wanna try out their recommed box specs.

dude Jmac u know ur shit. ur tha man, seriously

 
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