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<blockquote data-quote="T3mpest" data-source="post: 3425719" data-attributes="member: 560148">wow, no...&nbsp; F/S is the resonance frequency of the sub in free air.&nbsp;&nbsp; Below this frequency the sub will lose effeciency.&nbsp; At F/S inductance is at it&#039;s highest and effeciency peaks.Secondly, you&#039;ve said it about 100x in this thread and your still wrong.&nbsp; Multiple subs are more effecient than 1 larger one, for a variety of reasons.&nbsp; Assume aa single sub off off Y watts hits Xdecibels.&nbsp; Then add another sub without adding power, you&#039;re output is now X+3 decibels.&nbsp; By adding a sub, you gained output without adding power, secondly, since each driver is seeing less power, you can actually gain more than 3 decibels,&nbsp; if the first sub was having power compression issues.&nbsp; More potential output with with the same power is more effecient.Third a large speaker can play as high as a smaller one if they design it to, it&#039;s not a god given inherent part of the speaker.&nbsp; Inductance play a MUCH bigger role than cone area.</blockquote>

[QUOTE="T3mpest, post: 3425719, member: 560148"] wow, no... F/S is the resonance frequency of the sub in free air. Below this frequency the sub will lose effeciency. At F/S inductance is at it's highest and effeciency peaks. Secondly, you've said it about 100x in this thread and your still wrong. Multiple subs are more effecient than 1 larger one, for a variety of reasons. Assume aa single sub off off Y watts hits Xdecibels. Then add another sub without adding power, you're output is now X+3 decibels. By adding a sub, you gained output without adding power, secondly, since each driver is seeing less power, you can actually gain more than 3 decibels, if the first sub was having power compression issues. More potential output with with the same power is more effecient. Third a large speaker can play as high as a smaller one if they design it to, it's not a god given inherent part of the speaker. Inductance play a MUCH bigger role than cone area. [/QUOTE]

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